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3 years ago

What do you think would happen to a light bulb in the open circuit?

Chemistry

1 answer:

densk [106]3 years ago

6 0

Is there choices to this question? cant answer it without choices

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Aluminum has a density of 2.70 g/mL. Calculate the mass (in grams) of a piece of aluminum having a volume of 405 mL .

kirill [66]

MASS= Density times Volume
2.70*405
M= 1093.5

6 0

4 years ago

The positively charged dense center of a atom

Studentka2010 [4]

Nucleus is the answer, I believe

7 0

3 years ago

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MYTH OR FACT? Eating disorders occur only in fernales. *

sdas [7]

Answer:

myth

Explanation:

3 0

3 years ago

Lead metal can be extracted from a mineral called galena, which contains 86.6% lead by mass. a particular ore contains 68.5% gal

rjkz [21]

The volume of sphere can be calculated using the following formula:

$V=\frac{4}{3}\pi r^{3}$

Here, r is radius of the sphere which is 8 cm. Putting the value,

$V=\frac{4}{3}\pi r^{3}=\frac{4}{3}(3.14)(8 cm)^{3}=2143.57 cm^{3}$

This is equal to the volume of lead, density of lead is $11.34 g/cm^{3}$ thus, mass of lead can be calculated as follows:

$m=d\times V=11.34 g/cm^{3}\times 2143.57 cm^{3}=2.43\times 10^{4}g$

Let the mass of ore be 1 g, 68.5% of galena is obtained by mass, thus, mass of galena obtained will be 0.685 g.

Now, 86.6% of lead is obtained from this gram of galena, thus, mass of lead will be:

m=0.685×0.866=0.5932 g

Therefore, 0.5932 g of lead is obtained from 1 g of ore, if the efficiency is 100%.

For 92.5% efficiency, mass of lead obtained will be:

$m=\frac{92.5}{100}\times 0.5932=0.5487 g$

Thus, 1 g of lead obtain from $\frac{1}{0.5487}=1.822$ grams of ore.

Thus, $2.43\times 10^{4} g$ of lead obtain from:

$2.43\times 10^{4}\times 1.822=4.42\times 10^{4}g=44.2 kg$

Therefore, mass of ore required to make lead sphere is 44.2 kg.

4 0

3 years ago

Read 2 more answers

By December 31, 2003, concerns over arsenic contamination had prompted the manufacturers of pressure-treated lumber to voluntari

Musya8 [376]

Answer:

Explanation:

lewis structure can be defined as a process of how the valence shell electrons of a molecule is being arranged, the pattern of it arrangement and the relationship between the bonding atoms and the lone pairs present in the molecule.

In order to draw the Lewis structure for Arsenate ion $\mathsf{AsO \ _4^{3-}}$ , first thing is to count the valence electrons in the molecule. Once we determine the valence electrons, then we distribute them around the central atom. The Arsenate ion structure is tetrahedral in nature with a bond angle of 109.5° and it is sp³ hybridized.

7 0

4 years ago