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2 years ago

14

What happens to Hydrogen molecules after the light reaction in photosynthesis? Hydrogen is released into the atmosphere Hydrogen

bonds with Carbon Dioxide to form glucose Hydrogen bonds with Oxygen to form water.

1 answer:

vaieri [72.5K]2 years ago

5 0

Photosyntheis is a biochemical reaction that combines chemicals with biological species to produce energy. Atoms of hydrogen bond with carbon to form glucose.

<h3>What are the reactants and the products of the light reaction?</h3>

Carbon dioxide and hydrogen are the reactants that are used from the environment by the plants to make energy. Glucose and oxygen are the products.

The hydrogen atoms from the environment are absorbed by the plants and are combined with the carbon dioxide to yield glucose or sugar molecules for energy.

Therefore, option B. hydrogen and carbon dioxide react to produce glucose.

Learn more about photosynthesis here:

brainly.com/question/1388366

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How is a mixture such as a plate of pasta different from a mixture such as air

stealth61 [152]

Answer:

Well there is a lot of differences between the two. Its called homogeneous and Heterogeneous mixtures. Homogeneous mixtures are all the substances are evenly distributed throughout the mixture (salt water, air, blood). Heterogeneous mixtures are the substances that are not evenly distributed (chocolate chip cookies, pizza, rocks). So Pasta with sauce and meatballs is heterogeneous and air is homogeneous

HOPE THIS HELPS HAVE A GREAT DAY!!~

Explanation:

6 0

2 years ago

A small hole in the wing of a space shuttle requires a 20.7-cm² patch.

cricket20 [7]

The Patch's area of the space shuttle in km² is 2.07 × 10⁻⁹ km²

Given, that a space shuttle requires a 20.7 cm² patch

We have to convert the patch's area from cm² into km².

Unit conversion is a method in which we multiply or divide with a particular numerical factor and then finally round off to the nearest significant digits.

Patch area of the space shuttle is 20.7 cm²

1 cm = 0.00001 km

or, 1 cm² = (0.00001 km)²

or, 1 cm² = 10⁻¹⁰km²

20.7 cm² = 20.7 × 10⁻¹⁰km²

20.7 cm² = 2.07 × 10⁻⁹ km²

The patch area in square kilometers is 2.07 × 10⁻⁹ km²

To learn more about unit conversion, visit: brainly.com/question/11543684

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8 0

1 year ago

combustion analysis of a hydrocarbon produced 33.01g CO2 and 13.51g H2O. Calculate the empirical formula for the hydrocarbon

masya89 [10]

Answer:

$\rm CH_2$ .

Explanation:

Carbon and hydrogen are the only two elements in a hydrocarbon. When a hydrocarbon combusts completely in excess oxygen, the products would be $\rm CO_2$ and $\rm H_2O$ . The $\rm C$ and $\rm H$ would come from the hydrocarbon, while the $\rm O$ atoms would come from oxygen.

Look up the relative atomic mass of these three elements on a modern periodic table:

$\rm C$ : $12.011$ .
$\rm H$ : $1.008$ .
$\rm O$ : $\rm 15.999$ .

Calculate the molar mass of $\rm CO_2$ and $\rm H_2O$ :

$M(\mathrm{CO_2}) = 12.011 + 2 \times 15.999 = 44.009\; \rm g \cdot mol^{-1}$ .

$M(\mathrm{H_2O}) = 2 \times 1.008 + 15.999 = 18.015\; \rm g \cdot mol^{-1}$

Calculate the number of moles of $\rm CO_2$ molecules in $33.01\; \rm g$ of $\rm CO_2\!$ :

$\displaystyle n(\mathrm{CO_2}) = \frac{m(\mathrm{CO_2})}{M(\mathrm{CO2})} = \frac{33.01\; \rm g}{44.009\; \rm g\cdot mol^{-1}} \approx 0.7501\; \rm mol$ .

Similarly, calculate the number of moles of $\rm H_2O$ molecules in $13.51\; \rm g$ of $\rm H_2O\!$ :

$\displaystyle n(\mathrm{H_2O}) = \frac{m(\mathrm{H_2O})}{M(\mathrm{H_2O})} = \frac{13.51\; \rm g}{18.015\; \rm g\cdot mol^{-1}} \approx 0.7499\; \rm mol$ .

Note that there is one carbon atom in every $\rm CO_2$ molecule. Approximately $0.7501\; \rm mol$ of $\rm CO_2\!$ molecules would correspond to the same number of $\rm C$ atoms. That is: $n(\mathrm{C}) \approx 0.7501\; \rm mol$ .

On the other hand, there are two hydrogen atoms in every $\rm H_2O$ molecule. approximately $0.7499\; \rm mol$ of $\rm H_2O$ molecules would correspond to twice as many $\rm H\!$ atoms. That is: $n(\mathrm{H}) \approx 2 \times 0.7499 \; \rm mol\approx 1.500\; \rm mol$ .

The ratio between the two is: $n(\mathrm{C}): n(\mathrm{H}) \approx 1:2$ .

The empirical formula of a compound gives the smallest whole-number ratio between the elements. For this hydrocarbon, the empirical formula would be $\rm CH_2$ .

6 0

3 years ago

What does lower case k stand for?

DaniilM [7]

Just for more clarification, lowercase k is the rate constant. Uppercase K is the equilibrium constant. You can actually use k to find K (equilibrium constant). K=k/k' This means that the equilibrium constant is the rate constant of the forward reaction divided by the rate constant of the reverse reaction

4 0

3 years ago

What is one differrence between a mixture and a compound

Ann [662]

Answer:

A mixture can contain components in any proportions while a compound contains components in fixed proportions. All components in a mixture do not chemically react, while the components in a compound do react and their original properties are lost.

3 0

3 years ago