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murzikaleks [220]
3 years ago
13

How many molecules are in 15.0 g of oxygen gas (O2)?

Chemistry
1 answer:
frosja888 [35]3 years ago
3 0

Answer:

2.82*10^23

Explanation:

please see attached for work!

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A container of N2O3(g) has a pressure of 0.265 atm. When the absolute temperature of the N2O3(g) is tripled, the gas completely
Rzqust [24]

Answer:

1.59 atm

Explanation:

The reaction is:

N_{2}O_{3}(g) - - -> NO_{2}(g)+NO(g)

The dalton's law tell us that the total pressure of a mixture of gases is the sum of the partial pressure of every gas.

So after the reaction the total pressure is:

P_{total}=P_{NO_{2}}+P_{NO}

we don't include N_{2}O_{3} because it decomposed completely.

Assuming  ideal gases

PV=nRT

P= pressure, V= volume of the container, n= mol of gas, R=constant of gases and T=temperature.

so moles of N_{2}O_{3} is:

n_{N_{2}O_{3}}=\frac{P_{1}V}{RT_{1}}

from the  reaction stoichiometry (1:1) we have that after the reaction the number of moles of each product is the same number of moles of N_{2}O_{3}.

n_{NO_{2}}=\frac{P_{1}V}{RT_{1}}

n_{NO}=\frac{P_{1}V}{RT_{1}}

The partial pressure of each gas is:

P_{NO_{2}}=\frac{n_{NO_{2}*R*T_{2}}}{V}

P_{NO}=\frac{n_{NO}*R*T_{2}}{V}

so total pressure is:

P_{total}=(n_{NO_{2}}+n_{NO})*\frac{R*T_{2}}{V}

replacing the moles we get:

P_{total}=(2*\frac{P_{1}V}{RT_{1}})*\frac{R*T_{2}}{V}

We know that T2=3*T1

replacing this value in the equation we get:

P_{total}=2*\frac{P_{1}V}{RT_{1}}*\frac{R*3T_{1}}{V}

P_{total}=6*P_{1} = 6*0.265 atm = 1.59 atm

5 0
3 years ago
Based on the descriptions in the passage, which scientist proposed a model of the atom that matches the
Wittaler [7]

Answer:

J. J. Thomson

Explanation:

This is called the plum pudding model which was proposed by J. J. Thomson.

4 0
3 years ago
Which element has the electronic configuration, 1s22s22p63s23p64s1 ?
Alinara [238K]

Answer:

<u>Potassium element has the electronic configuration, 1s22s22p63s23p64s1.</u>

3 0
3 years ago
Explain the serious problem initially associated with Rutherfords atomic model
Ulleksa [173]
The problem initially associated with Rutherford’s atomic model was that accelerating charges should radiate energy. As electrons orbiting the nucleus were accelerating charges, they should lose energy and thus instantly spiral into the nucleus resulting in atoms, and thus all matter, collapsing.
7 0
3 years ago
Consider a reactant with an order of 1: What effect does that reactant have on the rate equation when the concentration is doubl
____ [38]

Answer:

1) The reaction rate is double with respect to that reactant

Explanation:

Hello,

By considering the rate law:

-r_A=kC_A

If we double the reactant A concentration, by definition, the rate will be doubled as well since the C_A power is one (order 1), this could be proved just by checking it out in the rate law.

Best regards.

6 0
4 years ago
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