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Sonbull [250]
2 years ago
8

A lightweight plastic rod has a mass of 2.0 kg attached to one end and a mass of 2.5 kg attached to the other end. The rod has a

length of 1.20 m. How far from the 2.0-kg mass should a string be attached to balance the rod
Physics
1 answer:
ipn [44]2 years ago
5 0

The distance from the 2.0 kg mass at which a string should be attached to balance the rod is 0.67 m.


<h3>What is distance?</h3>

Distance can be defined as the horizontal length between two points.

To calculate the distance at which the string must be attached to balance the rod, we use the formula below.

Formula:

  • m₁gx = m₂g(1.2-x)................. Equation 1

From the question,

Given

  • m₁ = 2.0 kg
  • m₂ = 2.5 kg
  • x = Distance of the string from the 2.0 kg mass
  • g = Acceleration due to gravity.= 9.8 m/s²

Substitute these values into equation 1

  • 2(9.8)(x) = 2.5(9.8)(1.2-x)

Solve for x

  • 19.6x = 29.4-24.5x

Collect like terms

  • 19.6x+24.5x = 29.4
  • 44.1x = 29.4
  • x = 29.4/44.1
  • x = 0.67 m

Hence, the distance from the 2.0 kg mass at which a string should be attached to balance the rod is 0.67 m.

Learn more about distance here: brainly.com/question/17273444

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SIZIF [17.4K]

Answer:

a) Weight of the rock out of the water = 16.37 N

b) Buoyancy force = 4.61 N

c) Mass of the water displaced = 0.47 kg

d) Weight of rock under water = 11.76 N

Explanation:

a) Mass of the rock out of the water = Volume x Density

   Volume = 470 cm³

   Density = 3.55 g/cm³

   Mass = 470 x 3.55 = 1668.5 g = 1.6685 kg

   Weight of the rock out of the water = 1.6685 x 9.81 = 16.37 N

b) Buoyancy force = Volume x Density of liquid x Acceleration due to gravity.

   Volume = 470 cm³

   Density of liquid = 1 g/cm³

   \texttt{Buoyancy force}= \frac{470\times 1\times 9.81}{1000} = 4.61 N

c) Mass of the water displaced = Volume of body x Density of liquid

   Mass of the water displaced = 470 x 1 = 470 g = 0.47 kg

d) Weight of rock under water = Weight of the rock out of the water - Buoyancy force

   Weight of rock under water = 16.37 - 4.61  =11.76 N

3 0
3 years ago
A heat engine operating between energy reservoirs at 20?c and 600?c has 30% of the maximum possible efficiency.
Anarel [89]
 <span>The maximum possible efficiency, i.e the efficiency of a Carnot engine , is give by the ratio of the absolute temperatures of hot and cold reservoir. 
η_max = 1 - (T_c/T_h) 

For this engine: 
η_max = 1 - [ (20 +273)K/(600 + 273)K ] = 0.66 = 66% 

The actual efficiency of the engine is 30%, i.e. 
η = 0.3 ∙ 0.664 = 0.20 = 20 % 

On the other hand thermal efficiency is defined as the ratio of work done to the amount of heat absorbed from hot reservoir: 
η = W/Q_h 

So the heat required from hot reservoir is: 
Q_h = W/η = 1000J / 0.20 = 5000J</span>
8 0
3 years ago
A 4 kilogram box is at rest on a frictionless floor. A net force of 12 newtons acts on it. What is the acceleration of the box?
Rashid [163]

Answer:

<h2>3 m/s^2</h2>

Explanation:

Step one:

given

Mass m= 4kg

Force F= 12N

Required

Acceleration the relation between force, acceleration, and mass is Newton's first equation of motion, which says a body will continue to be at rest or uniform motion unless acted upon by an external force

F=ma

a=F/m

a=12/4

a=3 m/s^2

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Is this answer correct?
alisha [4.7K]
Yes the answer is correct
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Dmitriy789 [7]

they are added vectorially. If htere is a resultant force, the thing acclerates. If they vectorially add to zero, thing doesn't move

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