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Sonbull [250]
1 year ago
8

A lightweight plastic rod has a mass of 2.0 kg attached to one end and a mass of 2.5 kg attached to the other end. The rod has a

length of 1.20 m. How far from the 2.0-kg mass should a string be attached to balance the rod
Physics
1 answer:
ipn [44]1 year ago
5 0

The distance from the 2.0 kg mass at which a string should be attached to balance the rod is 0.67 m.


<h3>What is distance?</h3>

Distance can be defined as the horizontal length between two points.

To calculate the distance at which the string must be attached to balance the rod, we use the formula below.

Formula:

  • m₁gx = m₂g(1.2-x)................. Equation 1

From the question,

Given

  • m₁ = 2.0 kg
  • m₂ = 2.5 kg
  • x = Distance of the string from the 2.0 kg mass
  • g = Acceleration due to gravity.= 9.8 m/s²

Substitute these values into equation 1

  • 2(9.8)(x) = 2.5(9.8)(1.2-x)

Solve for x

  • 19.6x = 29.4-24.5x

Collect like terms

  • 19.6x+24.5x = 29.4
  • 44.1x = 29.4
  • x = 29.4/44.1
  • x = 0.67 m

Hence, the distance from the 2.0 kg mass at which a string should be attached to balance the rod is 0.67 m.

Learn more about distance here: brainly.com/question/17273444

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Explanation:

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To find the answer, we have to know about the width of the central maximum.

<h3>How to find the distance between slit and the screen?</h3>
  • It is given that, wavelength 560 nm passes through a slit of width 0. 170 mm, and the width of the central maximum on a screen is 8. 00 mm.
  • We have the expression for slit width w as,

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  • Thus, distance between slit and the screen is,

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