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3 years ago

In a calorimeter, 10.0 g of ice melts at 0oC. The enthalpy of fusion of the ice is 334 J/g.

Chemistry

1 answer:

d1i1m1o1n [39]3 years ago

5 0

Answer:

Explanation:

In the problem above it is

q = mass x heat fusion

q = 10 g x 334 J/g = 3340 J. Since the ice is absorbing heat it is + 334 J.

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EDTA EDTA is a hexaprotic system with the p K a pKa values: p K a1 = 0.00 pKa1=0.00 , p K a2 = 1.50 pKa2=1.50 , p K a3 = 2.00 pK

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Answer:

Check the explanation

Explanation:

When,

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When,

pH = -log[H+] = 10.15

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Ka1 = 1 ; Ka2 = 0.0316 ; Ka3 = 0.01 ; Ka4 = 0.002 ; Ka5 = $7.4 X 10^{-7}$ ; Ka6 = $4.3 X 10^-11$

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= $1.26 X 10^{-61} + 1.8 X 10^{-51} + 8.1 X 10^{-43} + 1.12 X 10^{-34} + 3.17 X 10^{-27} + 3.3 X 10^{-23} + 1.83 X 10^{-23}$

= $5.12 X 10^{-23}$

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In descending order from top:

E
F
D
A
C
B

All you really need to do is remember the symbols of each, and you’ve got it.

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3 years ago

Read 2 more answers