Answer:
<u>A kangaroo hops 60 m to the east in 5 s. What is the kangaroo's average velocity? ... The kangaroo stops at a lake for a drink of water and then starts hopping again to the south. Each second, the kangaroo's velocity increases 2.5 m/s.</u>
Answer:
I = 1.525 kg.m/s
Explanation:
given,
mass of the ball = 0.165 Kg
height of drop, h = 1.25 m
ball rebound and reach to height, h' = 0.940 m
impulse = ?
using conservation of energy
Potential energy is converted into kinetic energy



v = 4.95 m/s
velocity of the ball after rebound
again using conservation of energy



v' = 4.29 m/s
impulse is equal to change in momentum
I = m ( v' - v )
I = 0.165 x ( 4.29 - (-4.95))
I = 1.525 kg.m/s
X component of force Fx=Fcos45=50×cos×45
Y component of force Fy=Fsin45=50×sin×45
Kepler's three laws of planetary motion can be stated as follows: (1) All planets move about the Sun in elliptical orbits, having the Sun as one of the foci. ... (3) The squares of the sidereal periods (of revolution) of the planets are directly proportional to the cubes of their mean distances from the Sun.
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