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2 years ago

If a Hh mom has an offspring with a hh dad, what is the probability that the offspring will have a dominant phenotype?

Chemistry

1 answer:

lisov135 [29]2 years ago

6 0

Answer:

I think 50%

Explanation:

im not really sure

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* The cost of table salt and table sugar is Rs 15 per kg.

Vilka [71]

Cost per mole

Table salt : Rs 0.878

Table sugar : Rs 23.63

<h3>Further explanation</h3>

Given

Cost table salt (NaCl) = 15/kg

Cost table sugar(sucrose-C12H22O11) = 69/kg

Required

cost per mole

Solution

mol of 1 kg Table salt(NaCl ,MW= 58.5 g/mol) :

$\tt mol=\dfrac{1000~g}{58.5}=17.09~mol=Rs~15\rightarrow 1~mol=Rs~0.878$

mol of 1 kg Table sugar(C12H22O11 ,MW= 342 g/mol) :

$\tt mol=\dfrac{1000}{342}=2.92~mol=Rs~69\rightarrow 1~mol=Rs~23.63$

6 0

2 years ago

The scientific study of the behavior of matter near 0 K is called

pshichka [43]

I think it is called condensated matter

8 0

2 years ago

Read 2 more answers

PLEASE HELP I HATE CHEM

Orlov [11]

This angle is obtained when all four pairs of outer electrons repel each other equally. The bond angles in ammonia and in water are less than 109.5° because of the stronger repulsion by their lone pairs of electrons.

8 0

3 years ago

What is the compound of libr

Katarina [22]

Answer:

Lithium Bromide

Explanation:

3 0

3 years ago

Which of the following substance is being reduced in the following reaction.? Cu (s) + 2AgNO3 (aq) + 2Ag (s) + Cu(NO3)2 (aq) A)

nikklg [1K]

<u>Answer:</u> The correct answer is Option A.

<u>Explanation:</u>

Oxidation reaction is defined as the reaction in which an atom looses its electrons. Here, oxidation state of the atom increases.

$X\rightarrow X^{n+}+ne^-$

Reduction reaction is defined as the reaction in which an atom gains electrons. Here, the oxidation state of the atom decreases.

$X^{n+}+ne^-\rightarrow X$

For the given chemical reaction:

$Cu(s)+2AgNO_3(aq.)\rightarrow 2Ag(s)+Cu(NO_3)_2(aq.)$

The half reactions for the above reaction are:

Oxidation half reaction: $Cu(s)\rightarrow Cu^{2+}(aq.)+2e^-$

Reduction half reaction: $2Ag^+(aq.)+2e^-\rightarrow 2Ag(s)$

From the above reactions, copper is loosing its electrons. Thus, it is getting oxidized.

Silver ion is gaining electrons and thus is getting reduced.

Hence, the correct answer is Option A.

3 0

2 years ago