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Mashutka [201]
2 years ago
13

You calibrate a set of automobile springs using a 25 kg car battery, attached to a rope that runs over a pulley, as shown in the

diagram.
You find that the spring is pulled out by 0.06 meters. Compute the spring constant, k, in N/m.
Just type in the numeric part of your answer, to the nearest 0.1 N/m.
Physics
1 answer:
Goshia [24]2 years ago
3 0

For an automobile spring using a 25 kg car battery, the spring constant is mathematically given as

K=4.08.3N/m

<h3>What is the spring constant?</h3>

Question Parameter(s):

a 25 kg car battery

The springs are pulled out by 0.06 meters

Generally, the equation for the Force  is mathematically given as

F=mg

Therefore

F=(25*9.8)

(25*9.8)=K(0.06)

K=4.08.3N/m

In conclusion, the spring constant

K=4.08.3N/m

Read more about Force

brainly.com/question/13370981

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We Know, F = m*a
Here, F = 34 N
m = 213 Kg

Substitute their values in the equation,
34 = 213 * a
a = 34/213
a = 0.159 m/s²

So, your final answer & the acceleration of the object would be 0.159 m/s²

Hope this helps!
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