Answer:
Enthalpy change = -44.12 kJ
Explanation:
<u>Given: </u>
ΔH°f(C2H6O(l)) = -277.69 kj/mol
ΔH°f(C2H4(g)) = 52.26 kj/mol
ΔH°f(H2O) = -285.83 kj/mol
<u>To determine:</u>
Enthalpy change for the formation of C2H6O
<u>Calculation:</u>
The given reaction is:

The enthalpy change for the reaction is given as;

where n(products) and n(reactants) are the moles of products and reactants
Substituting the appropriate values for n and ΔH°f:
![\Delta H = 1\Delta H^{0}f(C2H6O)-[1\Delta H^{0}f(C2H4)+1\Delta H^{0}f(H2O)]](https://tex.z-dn.net/?f=%5CDelta%20H%20%3D%201%5CDelta%20H%5E%7B0%7Df%28C2H6O%29-%5B1%5CDelta%20H%5E%7B0%7Df%28C2H4%29%2B1%5CDelta%20H%5E%7B0%7Df%28H2O%29%5D)
ΔH = -277.69-(52.26-285.83) = -44.12 KJ
Answer:
n = 0.072 mol
Explanation:
Given data:
Volume of gas = 3.80 L
Temperature of gas = 320 K
Pressure of gas = 0.496 atm
Number of moles of Ar gas = ?
Solution:
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
Now we will put the values.
n = PV/RT
n = 0.496 atm ×3.80 L / 0.0821 atm.L/ mol.K × 320 K
n = 1.88 /26.27 /mol
n = 0.072 mol
Amount (mol) of solute in 145.6 L of 0.850 M sodium cyanide
<h3>What is molarity?</h3>
Molar concentration (also known as molarity, quantity concentration, or substance concentration) is a measure of the concentration of a chemical species in a solution, specifically of a solute, in terms of amount of substance per unit volume of solution. The most often used unit for molarity in chemistry is the number of moles per liter, denoted by the unit symbol mol/L or mol/dm3 in SI units. A solution with a concentration of 1 mol/L is referred to as 1 molar, or 1 M.
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