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grin007 [14]
3 years ago
15

Which compound matches the ir spectrum best?

Chemistry
1 answer:
Maurinko [17]3 years ago
4 0
Small peak at 3000large peak at 1685F: it contains two benzene rings that is connected by a bunch of carbons and ketone-Explanation: The spectrum shows a stretching absorption consistent with a ketone functional group: carbonyl C=O stretching at ~1685 cm-1. (An aldehyde, by contrast, would also show a ~2700 cm-1 absorption for the carbonyl C-H stretch.) The C=O stretching frequency is consistent with an aromatic ketone, such as in compound F (1,4-diphenyl-1,4-butanedione). In contrast, an aliphatic ketone absorbs at higher energy (~1710 cm-1). The spectrum also shows the typical ~1600 & ~1500 cm-1 absorptions of a phenyl group.
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Dose your heart muscle get tired?<br> Yes or no.
WARRIOR [948]

Answer:

<em>no</em><em> </em>

Explanation:

our heart muscles never get tired, because it has to pump blood in our body 72 times a minute, it is made of special cardiac muscles which helps it to perform it's function without getting tired ....

<em>i</em><em> </em><em>hope</em><em> </em><em>it</em><em> </em><em>helped</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em>

5 0
3 years ago
How would you be able to tell if a train was moving?
lara [203]

Answer:

because I'm riding on it

8 0
3 years ago
Read 2 more answers
Be sure to answer all parts. A concentration cell consists of two Sn/Sn2+ half-cells. The electrolyte in compartment A is 0.23 M
kolbaska11 [484]

Answer:

Part A. The half-cell B is the cathode and the half-cell A is the anode

Part B. 0.017V

Explanation:

Part A

The electrons must go from the anode to the cathode. At the anode oxidation takes place, and at the cathode a reduction, so the flow of electrons must go from the less concentrated solution to the most one (at oxidation the concentration intends to increase, and at the reduction, the concentration intends to decrease).

So, the half-cell B is the cathode and the half-cell A is the anode.

Part B

By the Nersnt equation:

E°cell = E° - (0.0592/n)*log[anode]/[cathode]

Where n is the number of electrons being changed in the reaction, in this case, n = 2 (Sn goes from S⁺²). Because the half-reactions are the same, the reduction potential of the anode is equal to the cathode, and E° = 0 V.

E°cell = 0 - (0.0592/2)*log(0.23/0.87)

E°cell = 0.017V

3 0
3 years ago
What are the reagents for BaCO3(s)
Wittaler [7]

 The reagents for BaCO₃  is

    BaO and CO₂

      <em><u>Explanation</u></em>

Reagent is  a substance that bring  about a chemical reaction when added to a system.

Some  reagent  may be added to  see if a reaction has occurred.

 BaO  and  Co₂    are reagent  since they react  to produce BaCO₃ as below

BaO(s) + CO₂(g) → BaCO3(s)



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3 years ago
How the ph values can be used to compare the strength of hydrochloric acid and ethanoic acid?
devlian [24]
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