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2 years ago

List out the use of simple machine

Physics

1 answer:

jek_recluse [69]2 years ago

4 0

Explanation:

simple machine can multiplayer of speed and force

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One object has a charge of +5.0 · 10-6 c, and a second object has a charge of +2.0 · 10-6

ruslelena [56]

The electrostatic force between two charged objects is given by
$F=k \frac{q_1 q_2}{r^2}$
where
k is the Coulomb's constant
q1 is the charge of the first object
q2 is the charge of the second object
r is the separation between the two objects

In our problem:
$q_1=+5.0 \cdot 10^{-6} C$
$q_2 = +2.0 \cdot 10^{-6} C$
$r=0.5 m$
So if we plug these numbers into the equation, we can find the electrostatic force between the two objects:
$F=(8.99 \cdot 10^9 Nm^2C^{-2}) \frac{(5.0 \cdot 10^{-6} C)(2.0 \cdot 10^{-6}C)}{(0.5 m)^2}=0.36 N$

4 0

3 years ago

An object has kinetic energy of 324 J. If it’s speed is 9m/s, what is it’s mass?

harkovskaia [24]

It is 8 kilograms

I had to type more so here you go

6 0

3 years ago

Read 2 more answers

10. Calculate A ramp is

inna [77]

Answer: 3.33

Explanation:

MA = De/Dr

MA = 5.0/1.5

MA= 3.33

5 0

4 years ago

A 55.0-kg box rests on a horizontal surface. The coefficient of static friction between the box and the surface is 0.300. What h

MariettaO [177]

Answer:

161.86 N

Explanation:

mass of box m= 55.0 kg

weight of the box, mg= 55×9.81

g here is acceleration due to gravity =9.81 m/sec^2

coefficient of friction between the box and the surface μ= 0.3

the friction force F_s= μmg= 0.3×55×9.81

=161.86 N

to move the ball horizontal force required is 161.86 N

8 0

3 years ago

A point charge with charge q1 = 4.00 μC is held stationary at the origin. A second point charge with charge q2 = -4.40 μC moves

Bezzdna [24]

Answer:

W=0.94J

Explanation:

Electrostatic potential energy is the energy that results from the position of a charge in an electric field. Therefore, the work done to move a charge from point 1 to point 2 will be the change in electrostatic potential energy between point 1 and point 2.

This energy is given by:

$U=\frac{K\left |q_1 \right |\left |q_2 \right |}{r}\\$

So, the work done to move the chargue is:

$W=U_1-U_2\\W=\frac{K\left |q_1 \right |\left |q_2 \right |}{r_1}-\frac{K\left |q_1 \right |\left |q_2 \right |}{r_2}\\r_1=\sqrt{((0.155 m)^2+0 m)^2}=0.115m\\r_2=\sqrt{((0.245 m)^2+(0.270 m)^2}=0.365m\\W=K\left |q_1 \right |\left |q_2 \right |(\frac{1}{r_1}-\frac{1}{r_2})\\W=8.99*10^9\frac{Nm^2}{c^2}(4.00*10^{-6}C)(4.40*10^{-6}C)(\frac{1}{0.115m}-\frac{1}{0.365})\\W=0.94J$

The work is positive since the potential energy in 1 is greater than 2.

5 0

4 years ago

List out the use of simple machine​

List out the use of simple machine