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2 years ago

Chemical process where a solid turns into a gas without going through a liquid stage.

Physics

2 answers:

earnstyle [38]2 years ago

6 0

Answer:

B) sublimation

Explanation:

An example is the vaporization of frozen carbon dioxide (dry ice) at ordinary atmospheric pressure and temperature.

faust18 [17]2 years ago

6 0

Answer:

sublimation

Explanation:

sublimation, in physics, conversion of a substance from the solid to the gaseous state without its becoming liquid. An example is the vaporization of frozen carbon dioxide or dry ice(CO2)

or Solid Chlorine (Cl2) at ordinary atmospheric pressure and temperature. The phenomenon is the result of vapour pressure and

temperature relationships.

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What happens if 5 Protons combine with 4 neutrons.

lianna [129]

in the case of beryllium, a light metal, only the beryllium-9 isotope is stable with its 9 nucleons (i.e. 4 protons and 5 neutrons)

Hope this helps so sorry if it does not help

7 0

3 years ago

Read 2 more answers

An astronaut named Speedo takes a trip to Sirius, which is located a distance of 8 lightyears from the Earth. If the spaceship m

Softa [21]

Answer:

a. 10 years

b. 6 years

c. 12 years behind

Explanation:

speed of light c = 3x $10^{8}$ m/s

distance of sirius from earth = 8 lightyears = 8 x c x 60 x 60 x 24 x 365 = 252288000c meters

speed of spaceship = 0.8c

time taken to reach sirius = distance covered divided by speed

t = d/s = 252288000c/0.8c = 315360000 sec

1 year = 60 x 60 x 24 x 365 sec = 31536000 sec

315360000 sec = 315360000/31536000 = 10 yrs

the time as observed by Goslo will be shorter than the real time as measured within the ship due to relativistic effects. using the relativistic relation for time dilation we have

t' = t $\sqrt{1 - \frac{v^{2} }{c^{2} } }$

since v = 0.8c

v/c = 0.8

where t' is the relativistic time as observed by Goslo,

t is the time within the ship

t' = 10 x $\sqrt{1 - 0.8^{2} }$ = 6 yrs

If speedo turns around immediately after reaching sirius, his total distance will be 252288000c x 2 = 50457600c meter

time taken = 50457600c/0.8 = 630720000 sec = 20 yrs

time within the ship will be calculated from time dilation

t' = t $\sqrt{1 - \frac{v^{2} }{c^{2} } }$

t' = 20 x $\sqrt{1 - 0.8^{2} }$ = 378432000 sec = 12 years behind

4 0

3 years ago

How do air bags help us in a wreck?

andrew-mc [135]

It help protect you from coming out the car when you are in a accident

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3 years ago

A train brakes from 25 m/s to rest in 30 sec. What is its deceleration?

givi [52]

Answer:

a= -0.83m\s^2

Explanation:

a = v \ t

a = -25 \ 30 = -0.833 m\s^2

the object is slowing down 0.83 meter every second

8 0

3 years ago

Ball A is projected vertically upward at 30 m/s from a point P. Four seconds later, ball B is also launched vertically upwards f

nordsb [41]

The time of motion of ball A before they collide is 5.1 seconds.

<h3>Time of motion</h3>

The two balls will collide at a time "t" when they attain a certain height "h".

<h3>The equation of motion</h3>

The equation of motion of the two balls is given as follows;

when they collide;

A would have traveled, (t + 4) seconds
B would have traveled t seconds

$h_A = 30(t+ 4) - \frac{1}{2} g(t+ 4)^2\\\\h_B = 30t - \frac{1}{2} gt^2$

$h_B = h_A\\\\30t - \frac{1}{2} gt^2 = 30(t + 4) - \frac{1}{2} g(t + 4)^2\\\\30t - \frac{1}{2} gt^2 = 30t + 120- \frac{1}{2}gt^2- 4gt -8g\\\\0 = 120 -4gt -8g\\\\4gt +8g = 120\\\\4(9.8)t + 8(9.8) = 120\\\\39.2t + 78.4 = 120\\\\39.2 t = 41.6\\\\t = \frac{41.6}{39.2} \\\\t = 1.1 \ s$

Thus, the time of motion of ball A before they collide is (1.1 + 4) = 5.1 seconds.

Learn more about time of motion here: brainly.com/question/2364404

6 0

2 years ago