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3 years ago

What are examples or centripetal acceleration?

2 answers:

8 0

Centripetal acceleration is necessary, and is present, whenever any object
moves in a closed path, or along any part of a circular path. Some examples
I can think of are:

-- a planet or a comet in orbit around the sun
-- a moon in orbit around a planet
-- the little ball making circles around the spinning roulette wheel
-- a stone tied to the end of a string, when you spin it around your head
-- the end of the spinning string on a weed-whacker
-- the tip of the blade of a fan or a windmill
-- any little bit of rubber on a car tire or bicycle tire, when they're moving
-- a strawberry seed spinning around the inside of the blender jar when you're
making a smoothie
-- a car driving around a curve in the road
-- you on almost any amusement park ride; whenever you're not moving in a
straight line, you're experiencing centripetal acceleration.

zloy xaker [14]3 years ago

4 0

<u>centripedal acceleration :</u>

⇒ the moon in orbit around a planet (or the sun).
⇒ The Earth (or an other planet) in orbit around the sun.

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Which illustrates the law of conservation of matter? A. producers because they create new matter B. decomposers because they des

Klio2033 [76]

D. compost bins because they recycle matter into a new form

Explanation:

The law of conservation of matter is about the creation and how matter is being transferred. According to the law, the matter cannot be destroyed. The matter should always be transferred from one form to another in the universe. There is never destruction of matter happens. There is also one more point to it, as it cannot be destroyed it also cannot be created.
Here in the options, option A tells us the creation which is not possible, option B says about the destruction of matter which is not true according to the law, C is about storing the matter which will not happen because its get transferred and D is the correct option because it talks about the recycle/ transfer of matter.

7 0

3 years ago

Light of wavelength 480 nm illuminates a pair of slits separated by 0.27 mm. If a screen is place 1.7 m from the slits, determin

Dahasolnce [82]

Answer:

Δy = 6.05 mm

Explanation:

The double slit phenomenon is described by the expression

d sin θ = m λ constructive interference

d sin θ = (m + ½) λ destructive interference

m = 0,±1, ±2, ...

As they tell us that they measure the dark stripes, we are in a case of destructive interference, let's use trigonometry to find the sins tea

tan θ = y / x

y = x tan θ

In the interference experiments the measured angle is very small so we can approximate the tangent

tan θ = sin θ / cos θ

cos θ = 1

tan θ = sin θ

y = x sin θ

We substitute in the destructive interference equation

d (y / x) = (m + ½) λ

y = (m + ½) λ x / d

The first dark strip occurs for m = 0 and the third dark strip for m = 2. Let's find the distance for these and subtract it

m = 0

y₀ = (0+ ½) 480 10⁻⁹ 1.7 / 0.27 10⁻³

y₀ = 1.511 10⁻³ m

m = 2

y₂ = (2 + ½) 480 10⁻⁹ 1.7 / 0.27 10⁻³

y₂ = 7.556 10⁻³ m

The separation between these strips is Δy

Δy = y₂-y₀

Δy = (7.556 - 1.511) 10⁻³

Δy = 6.045 10⁻³ m

Δy = 6.05 mm

5 0

3 years ago

Stronger acids have more _______

mario62 [17]

Examples of strong acids are hydrochloric acid (HCl), perchloric acid (HClO4), nitric acid (HNO3) and sulfuric acid (H2SO4). ... For example, hydrogen chloride is a strong acid in aqueous solution, but is a weak acid when dissolved in glacial acetic acid.

7 0

3 years ago

If the pressure inside the cylinder increases to 1.6 atm, what is the final volume, in milliliters, of the cylinder?

Bess [88]

This is an incomplete question, here is a complete question.

The air in the cylinder with a piston has a volume of 220 mL and a pressure of 650 mmHg.

If the pressure inside the cylinder increases to 1.6 atm, what is the final volume, in milliliters, of the cylinder?

Answer : The final volume of the cylinder is, 117.6 mL

Explanation :

Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.

$P\propto \frac{1}{V}$