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Lostsunrise [7]
3 years ago
11

What are examples or centripetal acceleration?

Physics
2 answers:
Marina86 [1]3 years ago
8 0
Centripetal acceleration is necessary, and is present, whenever any object
moves in a closed path, or along any part of a circular path.  Some examples
I can think of are:

-- a planet or a comet in orbit around the sun
-- a moon in orbit around a planet
-- the little ball making circles around the spinning roulette wheel
-- a stone tied to the end of a string, when you spin it around your head
-- the end of the spinning string on a weed-whacker
-- the tip of the blade of a fan or a windmill
-- any little bit of rubber on a car tire or bicycle tire, when they're moving
-- a strawberry seed spinning around the inside of the blender jar when you're
making a smoothie 
-- a car driving around a curve in the road
-- you on almost any amusement park ride;  whenever you're not moving in a
straight line, you're experiencing centripetal acceleration.
zloy xaker [14]3 years ago
4 0
<u>centripedal acceleration :</u>

⇒ the moon in orbit around a planet (or the sun).
⇒ The Earth (or an other planet) in orbit around the sun.


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What causes the angle of the sun’s rays to change during the year on Earth?
amm1812

The tilt of Earth's axis hope this helps

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4 years ago
Can an object's average velocity equal zero when object's speed is greater than zero.
notsponge [240]
No, because the magnitude of the velocity is always greater than speed.
6 0
3 years ago
By what mechanism is a person injured when he or she falls from a significant height? Select one: a. Kinetic energy is converted
oksano4ka [1.4K]

Answer:

d. Potential energy is converted to kinetic energy; the kinetic energy is then converted into the work of bringing the body to a stop.

Explanation:

- At the beginning of the falls, when the person is still at a certain height h, the person has gravitational potential energy:

U = mgh

where m is the mass of the person, g the acceleration due to gravity, h the height above the ground.

- As the person falls down, h decreases, so the potential energy decreases; according to the law of conservation of energy, potential energy is converted into kinetic energy, since the speed of the person increases:

K=\frac{1}{2}mv^2

where v is the speed.

- Just before hitting the ground, all the potential energy has been converted into kinetic energy

- When the person hits the ground, he/she comes to a stop: so work is done by the ground on the person, because the ground applied a force required to stop the person, and the kinetic energy "lost" by the person is equal to the work done by the ground to bring the body to a stop.

8 0
4 years ago
संचित होगी?
mezya [45]

Answer:

The formula i use is called, Product over Sum. Which means it is figured by their multiplied resistances divided by their sum. It is applied by pairs of known resistances. Starting with 20 and 30 Ohms, 600 is divided by 50. Using a quick mental calculation, the first pair has a resistance of 12 Ohms. Then, do that with 12 Ohms and 10 Ohms. 120 Ohms divided by 22. The answer is, about 5.5 Ohms. By this interesting development, we are reminded that resistances in parallel are effectively never more than the least one.

The students decide to assemble a convenient experiment and will run one amp through them all in parallel and measure their voltage. Watching the Amperage gauge on their teacher’s power supply. As one begins to turn it up to an Amp, another is watching its voltage till an Amp is perfectly applied. But as they carefully do that, watching the Amp gauge, another screams, their 10 Ohm resistor turns black and smokes as they were only pumping out 2 or 3 tenths of an Amp. What happened? What did they need, to make this simple experiment not so embarass-king?

Buy room air freshener?

3 0
3 years ago
Consider a 50-turn circular loop with a radius of 1.75 cm in a 0.25-T magnetic field. This coil is going to be used in a galvano
aleksandr82 [10.1K]

Answer:

(a) τ = 0.782Nm

(b) x = 0.747Nm/rad

Explanation:

Given that

N = 50, r = 1.75cm = 1.75×10-²m, B = 0.25T, I = 65A.

The torque on a coil of N turns of wire is given by

τ = NIAB

From the problem statement, this torque can also be represented by an angular form of hooke's law.

τ = xθ

Where N = number of turns, I = current in amps (A), A = area in m², B = magnetic field strength in T, x = torque constant in Nm/rad and θ = angular displacement.

Area A = πr² = π×(1.75×10-²)² = 9.62×10-⁴m²

(a) τ = NIAB = 50×65×9.62×10-⁴×0.25

τ = 0.782Nm

(b) x = τ/θ

θ = 60° = 60×2π/360 = π/3 rad

x = 0.782/(π/3)

x = 0.747Nm/rad.

3 0
3 years ago
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