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2 years ago

Question 1 of 10

Physics

1 answer:

Dahasolnce [82]2 years ago

3 0

Answer:

They have the same rate of motion.

Explanation:

Electromagnetic radiation is a type of energy that is commonly known as light. Generally, light travels in waves, and all electromagnetic radiation travels at the same speed, which is about 3.0 × 108 ms− 1 through a vacuum.

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How are galaxies organized and distributed within the universe

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The galaxies aren't distributed randomly throughout the universe but they are grouped in gravitationally bound clusters.

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3 years ago

Read 2 more answers

Thank you in advance

Musya8 [376]

$m1 = \frac{- v2m2 - m2v1}{v2 - v1}$

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3 years ago

Which light waves travel faster radio waves or gamma waves?

qaws [65]

Answer:

In a vacuum all light travels the same speed no matter what the wavelength or frequency. Gamma radiation has a smaller wavelength and larger frequency, radio waves a smaller frequency and larger wavelength.

Explanation:

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3 years ago

If the gravitational field strength at the top of Mount Everest is 9.772 N/kg, approximately how tall (in feet) is

Delicious77 [7]

Answer:

The height of the Everest mountain is, x = 8514.087 m

Explanation:

Given data,

The gravitational field strength at the top of mount Everest, gₓ = 9.772 m/s²

The formula for gravitational field strength is,

Where, x is the height from the surface of the Earth

Therefore,

(R+x)² = GM/gₓ

x = √(GM/gₓ) - R

Substituting the values,

x = √(6.67408 x 10⁻¹¹ X 5.972 x 10²⁴ / 9.772) - 6.378 x 10⁶

x = 8514.087 m

Therefore, the height of the Everest mountain is, x = 8514.087 m

6 0

3 years ago

Vector A has a magnitude of 8.0 m and points east, vector B has a magnitude of 6.0 m and points north and vector C has a magnitu

sineoko [7]

Answer:

The answer is E) 6.7m at an angle 63° north of east

Explanation:

We begin by writing out our given vectors A,B and C in their respective rectangular Cartesian coordinate form. which are given as A=8i, B=6j and C= -5j (negative because it points towards west which is towards the left which is taken as the negative direction).Now we simply add all three to obtain our final vector given by,

$V=A+B+C\\V=8i + 6j - 5i\\V=3i + 6j$

In the last step we just added the like components. Now we will have to calculate the magnitude and angle of V(with respect of the east direction), which is given by,

$|V| = \sqrt{3^2 + 6^2} =6.7m\\\\\alpha =tan^{-1} (6/3)=tan^{-1} (2) = 63.4$

the angle alpha is always calculated with respect to the horizontal positive axis, and since both components of the vector are positive the vector lies in the first quadrant. Hence the 63° angle north of east is justified. The term north of east means the angle formed in moving from east towards the north that is from the positive horizontal axis to the positive vertical axis.

8 0

3 years ago