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Arlecino [84]
1 year ago
7

2.75 x 4 x 10000 (with explanation)

Chemistry
1 answer:
Murljashka [212]1 year ago
6 0

Answer:

110000

Explanation:

Multiply 2.75 by 4. is 11

Multiply 11 by 10000. is

110000

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C6H12O6 + 6 O2 --> 6 CO2 + 6 H2O + energy In the reaction listed above, 1 molecule of glucose reacts with 6 molecules of oxyg
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Answer:

  • Third choice:<em> energy present in the glucose and oxygen that is not needed for the formation of carbon dioxide and water is released to form energy/ATP.</em>

Explanation:

<u>1) Chemical equation (given):</u>

  • C₆H₁₂O₆ + 6 O₂ --> 6 CO₂ + 6 H₂O + energy

<u>2) Chemical potential energy:</u>

Each compound stores chemical potential energy.  This energy is stored in the chemical bonds.

Due to every substance has its own unique chemical potential energy, when a chemical reaction takes plase, yielding to the change of some substances, some energy is absorbed (when bonds are formed) and some energy is released (when bonds are broken).

<u>3) Conservation of energy:</u>

Then, if the sum of the bond energies of the final products is less than the sum of the bond energies of the reactants, the<em> law of conservation of energy</em> rules that the difference between the total energies of the products and reactants must be released to the surroundings.

That is what is happening in the given reaction:

  • C₆H₁₂O₆ + 6 O₂ --> 6 CO₂ + 6 H₂O + energy

The term energy in the product side means that energy is conserved because it is being released due to the the glucose and oxygen (reactant side) have more energy stored in their bonds than the energy needed for the formation of carbon dioxide and water, so that excess of energy is released to form energy/ATP.

<u>Summarizing:</u>

  • The energy on the product side added to the energy of carbon dioxide and water equals the energy of the glucose and oxygen and the final balance is:

  • ∑ Energy of the reactants = ∑energy of the products + released energy, supporting the law of conservation of energy.
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Marrrta [24]

Answer:

Other side

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In the numerator and not the denominator

Explanation:

To isolate a single variable when rearranging equations, move all other variables to the other side of the equation by using the opposite function on them and remembering to perform that operation on both sides of the equation. Make sure the rearrangement has the target variable in the numerator, not the denominator.

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