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Marat540 [252]
2 years ago
12

When astronauts aboard the space shuttle look down at the earth, its atmosphere appears blue. Why?.

Physics
1 answer:
Alex777 [14]2 years ago
8 0

Answer:

Reflection

Explanation:

<em>The particles in the atmosphere only reflect the color blue and and all others are absorbed. Only the reflected colors can be seen from our eyes not the absorbed ones</em>

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CHEGG 42 mT magnetic field points due west. If a proton of kinetic energy 9 x 10-12 J enters this field in an upward direction,
alexdok [17]

Answer:

The  magnitude of the Force is  F = 697 *10^{-15}N  and the direction is South  

Explanation:

From the question we are told that

         The magnetic field point due west and since East point toward the positive x -axis(i)  then this magnetic field would be mathematically represented as

                \= B = 42(-i)mT = 42*10^{-3} (-i) T

Now from the question we are told that the kinetic energy is

             KE = 9*10^{-12}J

Now this kinetic energy can be mathematically represented as

                  KE = \frac{1}{2}mv^2

Where m is the mass of proton which has a general value of

           m = 1.67*10^{-27}kg

Now making the subject of the formula

                v = \sqrt{\frac{KE}{0.5 * m} }

Substituting values we have

               v = \sqrt{\frac{9*10^{-12}}{0.5 * 1.67*10^{-27}} }

                 = 10.37*10^7m/s

Now from the question we are told that proton is moving upward which is in the positive z direction so the velocity of the proton would be in the positive

So the velocity would be

            \= v = 10.37*10^{7} \r k \ m/s

Now the magnetic Force can be mathematically represented as

          \= F = q \= v * \=  B

Where q is the charge on the proton which has a general value of  q =1.6*10^{-19}C

Now substituting the value

          \= F = 1.6*10^{-19 } * (10.37 *10^7) \r k * (42 *10^{-3})(-i)

              = 697*10^{-15} J

Now according to Fleming's left hand rule the direction of the magnetic force is south toward the negative Y - direction (-j)

So the force can be denoted as

                 \= F = 697*10^{-15}(-j) N

             

             

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