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2 years ago

When astronauts aboard the space shuttle look down at the earth, its atmosphere appears blue. Why?.

Physics

1 answer:

Alex777 [14]2 years ago

8 0

Answer:

Reflection

Explanation:

<em>The particles in the atmosphere only reflect the color blue and and all others are absorbed. Only the reflected colors can be seen from our eyes not the absorbed ones</em>

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An ideal gas is confined within a closed cylinder at atmospheric pressure (1.013 * 105 Pa) by a piston. The piston moves until t

likoan [24]

Answer:

$911700\ \text{Pa}$

Explanation:

$P_1$ = Initial pressure = $1.013\times 10^5\ \text{Pa}$

$V_1$ = Initial volume

$V_2$ = Final volume = $\dfrac{V_1}{9}\\\Rightarrow \dfrac{V_1}{V_2}=9$

Temperature is the same in the initial and final state

From the ideal gas law we have

$P_1V_1=P_2V_2\\\Rightarrow P_2=\dfrac{P_1V_1}{V_2}\\\Rightarrow P_2=P_1\times9\\\Rightarrow P_2=1.013\times 10^5\times 9\\\Rightarrow P_2=911700\ \text{Pa}$

The final pressure of the system is $911700\ \text{Pa}$ .

5 0

3 years ago

A probe orbiting Venus exerts a gravitational force of 2.58 × 103 N on Venus. Venus has a mass of 4.87 × 1024 kg. The mass of th

Westkost [7]

<h3>The correct answer is:</h3><h2>9.08 x 10⁶ meters.</h2><h2 /><h3>Explanation:</h3>

Fg = 2.58 x 10³ N

Mv = 4.87 x 10²⁴ Kg

Md = 655 Kg

So, Fg = G Mv Mp / r²

By putting in the values,

r² = 8.2466 x 10¹³

<h2>r = 9.08 x 10⁶ meters.</h2>

3 0

3 years ago

Read 2 more answers

17. Suppose you attach the object with mass m to a vertical spring originally at rest, and let it bounce up and down. You releas

insens350 [35]

Answer:

See below ↓

Explanation:

<u>Step 1 : Diagram</u>

In attachment

We choose the system to be the spring, the block, and the Earth and it is isolated
We put all the data in the figure we have created and create a zero level (initial height) of the block to be yₓ = 0 and the final position, when it stops and moves upwards again, to be yₙ = -A
No external forces are exerted on the system and no energy comes in or out of the system
Hence,

⇒ ΔE = 0

⇒ Eₙ - Eₓ = 0

⇒ Eₙ = Eₓ

⇒ Kₙ + Uₙ + Pₙ = Kₓ + Uₓ + Pₓ

Final kinetic energy is 0 at the lowest point

⇒ Uₙ + Pₙ = Uₓ + Pₓ

Initial potential energy is 0 [zero level = initial height]

⇒ Uₙ + Pₙ = Uₓ

And we know that spring was originally at normal length, so initial spring energy is also 0

⇒ Uₙ + Pₙ = 0

⇒ 1/2kxₙ² + mgyₙ = 0

⇒ 1/2kxₙ² = -mgyₙ

We know xₙ = A and yₙ = -A from the diagram

⇒ 1/2kA² = -mg(-A)

⇒ 1/2kA² = mgA

⇒ [1/2kA = mg]

Spring force is given by : F = -kx
Note : x = A

⇒ F = kA

⇒ k = F/A

⇒ Plug 'k' into the equation found at the end of Step 3

⇒ 1/2(F/A)(A) = mg

⇒ 2F = mg

⇒ F = 2mg (a)

We know the spring will stop oscillating and be at rest at the new equilibrium position of the system

⇒ F - mg = 0

⇒ F = mg

We know that :

⇒ F = -kx

In the case x = yₙ

⇒ kyₙ = mg

⇒ yₙ = mg/k

⇒ yₙ = 0.25 x 9.8 / -10

⇒ yₙ = -0.245 m

⇒ yₙ = A

⇒ yₙ = 0.245 m (b)

v(max) = Aω
v(max) = A√k/m
v(max) = 0.245 x √(10/0.25)
v(max) = 1.55 m/s (c)

8 0

2 years ago

A compact car and a large truck collide head on and stick together. Which undergoes the larger change in the magnitude of moment

hram777 [196]

Answer:

Neither. They will have equal change in the magnitude of momentum.

Explanation:

Change in in momentum of a body is calculated as follows:

ΔP = FΔt

where ΔP is the change in momentum

and F is the force exerted on the object

and Δt is the change in time during the impact

The time it takes for the impact is the same for both objects. Also, according to Newton's third law, when object A exerts a force on on object B, B exerts an equal(magnitude wise) but opposite force on A. Therefore the value of F is also equal. This tells us that the magnitude of impulse will be the same for both the fly and the truck

3 0

4 years ago

A single, nonconstant force acts in the + x ‑direction on an object of mass M that is constrained to move along the x ‑axis. As

andre [41]

Answer:

Velocity $V = \frac{dx}{dt} = \frac{d}{dt} (P + Qt + Rt^{3})$