Momentum of car
Given: Mass m= 1,400 Kg; V = 6.0 m/s
Formula: P = mv
P = (1,400 Kg)(6.0 m/s)
P = 8,400 Kg.m/s
Velocity of the rider to have the same momentum as a car.
Mass of rider and bicycle m = 100 Kg
P = mv
V = P/m
V = 8,400 Kg.m/s/100 Kg
V = 84 m/s
Answer:
11109.825 N
Explanation:
Given Data:
total mass =m=1510 kg
initial acceleration (a) =0.75g ( g=9.81 m/s² )
F=ma
= (1510)*( 0.75*9.81)
= 11109.825 N
Answer:
Any other language I don't know this language
Answer:
![1.1\cdot 10^{-10}C](https://tex.z-dn.net/?f=1.1%5Ccdot%2010%5E%7B-10%7DC)
Explanation:
The electric field produced by a single point charge is given by:
![E=k\frac{q}{r^2}](https://tex.z-dn.net/?f=E%3Dk%5Cfrac%7Bq%7D%7Br%5E2%7D)
where
k is the Coulomb's constant
q is the charge
r is the distance from the charge
In this problem, we have
E = 1.0 N/C (magnitude of the electric field)
r = 1.0 m (distance from the charge)
Solving the equation for q, we find the charge:
![q=\frac{Er^2}{k}=\frac{(1.0 N/c)(1.0 m)^2}{9\cdot 10^9 Nm^2c^{-2}}=1.1\cdot 10^{-10}C](https://tex.z-dn.net/?f=q%3D%5Cfrac%7BEr%5E2%7D%7Bk%7D%3D%5Cfrac%7B%281.0%20N%2Fc%29%281.0%20m%29%5E2%7D%7B9%5Ccdot%2010%5E9%20Nm%5E2c%5E%7B-2%7D%7D%3D1.1%5Ccdot%2010%5E%7B-10%7DC)
Answer:
1) The matter absorbs or reflects the light
2) Lens
3) <u><em>Concave</em></u>- curves inwards. Diverges light
b.<u><em>Convex</em></u>- curves outward. Converges light
4) The image is real if the distance of the object from the lens is greater than the focal length and virtual if it is less than the focal length
5) Lens and, for convex lenses, on the distance between the lens and the object.
6) Index of refraction?
Explanation:
I hope this helped you, sorry if anything is wrong