Answer:
1. The image is real
2. 5.85
3. h' = 3.05 mm
4. The image is upright
Explanation:
1. Start with the first lens and apply 1/f = 1/p + 1/q
1/5.01 = 1/13.7 + 1/q
q = 7.90 cm
Since that distance is behind the first lens, and the second lens is 62.5 cm behind the first lens, that distance is 62.5 - 7.90 = 54.6 cm in front of the second lens, and becomes the object for that lens, thus,
1/25.9 = 1/54.6 + 1/q
q = 49.3 cm behind the second lens
Using that information, since q is positive, the image is real
2. Also, using that information, you have the second answer, which is 49.3 cm
The height can be found from the two magnifications.
m = -q/p
m1 = -7.9/13.7 = -.577
m2 = -49.3/54.6 = -.903
Net m = (-.577)(-.903) = .521
Then, m = h'/h
.521 = h'/5.85
3. h' = 3.05 mm
4. For the fourth answer, since the overall magnification is positive, the final image is upright
Answer:
Explanation:
By using relation,
Speed of light = frequency × wavelength (in m)
(i)1.5cm
(ii)4.5cm
(iii)10cm
Answer:
One of the leading theories of hot-Jupiter formation holds that gas giants in distant orbits become hot Jupiters when the gravitational influences from nearby stars or planets drive them into closer orbits. They formed as gas giants beyond the frost line and then migrated inwards.
Explanation:
In the migration hypothesis, a hot Jupiter forms beyond the frost line, from rock, ice, and gases via the core accretion method of planetary formation. The planet then migrates inwards to the star where it eventually forms a stable orbit. The planet may have migrated inward smoothly via type II orbital migration.
Hot-Jupiters are heated gas giant planets that are very close to their stars, just a few million miles distant and orbiting their stellar hosts in just a few days. The reason why there isn't one in our Solar System is down to its formation. All gas giants form far from their star but then some migrate inwards.
Hot-Jupiters will just happen to transit about 10% (that is, since orbital planes) this is consistent with the rate expected from geometry of . The actual frequencies of hot Jupiters around normal stars is surprisingly hard to figure out.
Answer:
22m/s
Explanation:
Step one:
Given data
Initial velocity of roller coster u= 6 m/s
Final velocity v= 72m/s
time t= 3 seconds
Required
We want to solve for the acceleration of the roller coster
Step two:
From the formula
acceleration= v-u/t
substitute
a= 72-6/3
a=66
/3
a= 22 m/s
The cars acceleration 22m/s