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wariber [46]
2 years ago
7

Determine the number of grams of NaHCO3 that are in one liter of a 2.1 M solution

Chemistry
1 answer:
svlad2 [7]2 years ago
3 0

\text{Molarity,}~ S= 2.1~mol/L\\\\\text{Molar mas of}~ NaHCO_3, ~M=84~~ g/mol\\\\\text{Volume,}~~ V = 1 ~L\\\\\text{Mass,} ~w = ?

\text{ We know that,}\\\\~~~~~S = \dfrac{n}V\\\\\implies n = SV\\\\\implies \dfrac{w}{M} = SV\\\\\implies w = SVM\\\\\implies w= 2.1 \times 1 \times 84\\\\\implies w =176.4 ~ g

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complete question is:

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Hello there!

In this case, since the scaling factor is defined as the ratio of the molar mass of the molecular formula (complete) to the empirical formula (simplified), it is possible to compute it for the empirical formula of CH2O whose molar mass is 30 g/mol (12+2+16) as shown below:

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Explanation:

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