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gulaghasi [49]
2 years ago
6

Which statement best describes balancing equations and the law of conservation of mass?

Physics
1 answer:
Dmitrij [34]2 years ago
5 0

Answer:

The number of atoms is the same in the reactants and in the products, and the total mass is the same in the reactants and in the products.

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Determine the potential difference between two charged parallel plates that are 0.10 cm apart and have an electric field strengt
NikAS [45]
Formula for Electric Field strength , E =  V/d

where V = Voltage in volts, and d = distance of separation in meters.

d = 0.1 cm ,    E = 12 V/cm

E = V/d =  15 / 0.025

V = E*d

V = 12 * 0.1 = 1.2

Potential difference, V = 1.2 V 
5 0
3 years ago
Dormancy helps plants survive freezing temperatures and lack of
Paraphin [41]
Dont be rude she's asking you that the question Ugh 
Oh and the answer is Liquid water even though water is already liquid ok its just water okay
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3 years ago
Read 2 more answers
Solve a hollow steel shaft has an outside diameter of 100mm and inside diameter of 75 mm.the shaft is subjected to a pure torque
FrozenT [24]
  • The maximum shearing stress in hollow shaft is 66.125 MPa.
  • The magnitude of angle of twist is 0.0279 rad.
  • The power generated by the shaft is  157 kW.

<h3>What is power ?</h3>

Power in a rotating body like shaft is the product of Torque and the angular speed of that shaft.

P = Tω

The Torque is related to the shearing stress is

T = π/16 xτ(Do³ -Di³)

* Given is the Torque T= 7.5 kN.m, the inner diameter Di = 0.075m, outer diameter Do= 0.1m

Then, the maximum shearing stress will be

7.5 x 10³ =  π/16 xτ x (0.1³ - 0.075³)

τ = 66.125 MPa

Thus, the shearing stress is 66.125 MPa.

* From the Torque equation

T/J = Gθ/l

Where, J = π/32 (Do⁴ -Di⁴) = 0.00000671 m⁴

l = length of shaft = 2m, modulus of rigidity G = 80GPa = 80x 10⁹ Pa.

Substitute the values, we get the angle of twist

7.5 x10³ /0.00000671 = 80x 10⁹xθ/2

θ = 0.0279 rad.

Thus, the angle of twist is0.0279 rad.

* Power generated by the shaft is

P = 2πNT/60

where N = revolution/ minute = 200

Put the values, we get

P =  2π x 200 x 7500/60

P = 157 kW.

Thus, the power generated is 157 kW.

Learn more about power.

brainly.com/question/15120631

#SPJ1

5 0
2 years ago
Two solid spheres of radius R made of the same type of steel are placed in contact. The magnitude of the gravitational force the
dimulka [17.4K]
F1 = G * m*m / [2r]  ^2 = G * m^2 / 4r^2

Given the the mass is proportional to the volume and the volume is proportional to r^3, the mass of each big sphere is  3^3 = 27 times the mass of the small spheres. And the distance between the centers is 3r + 3r = 6r

F2 = G * [27m * 27m]/* [6r]^2 = G* 27^2 m^2 / 36r^2 = 81 G*m^2 / 4r^2 = 81*F1

Therefore, F2 = 81F1

Answer: option D) 81F1.
3 0
3 years ago
AYUDA!!!!!
ZanzabumX [31]

Answer:

a) El valor de la densidad es 0.79 \frac{g}{cm^{3} } o 790 \frac{g}{cm^{3} }

b) El peso especifico es 7749.9\frac{N}{m^{3} }

Explanation:

a) La densidad se define como la propiedad que tiene la materia, ya sean sólidos, líquidos o gases, para comprimirse en un espacio determinado. En otras palabras, la densidad es una magnitud que permite medir la cantidad de masa que hay en determinado volumen de una sustancia. Entonces, la expresión para el cálculo de la densidad es el cociente entre la masa de un cuerpo y el volumen que ocupa:

d=\frac{m}{V}

En este caso:

  • masa= 237 g= 0,237 kg (siendo 1000 g= 1 kg)
  • volumen= 300 cm³= 0,0003 m³ (siendo 1 cm³= 0,000001 m³)

Reemplazando:

d=\frac{237 g}{300cm^{3} } →  d=0.79 \frac{g}{cm^{3} }

d=\frac{0,237 kg}{0,0003m^{3} }→  d=790 \frac{g}{cm^{3} }

<u><em>El valor de la densidad es 0.79 </em></u>\frac{g}{cm^{3} }<u><em> o 790 </em></u>\frac{g}{cm^{3} }<u><em></em></u>

b) El peso específico es la relación existente entre el peso y el volumen que ocupa una sustancia en el espacio.

Entonces, en este caso, siendo el peso:

P= m*g= 0,237 kg* 9,81 \frac{m}{s^{2} }= 2,32497 N

el peso especifico es calculado como:

Pe=\frac{Peso}{Volumen}= \frac{2,32497N}{0,0003 m^{3} }

Pe= 7749.9\frac{N}{m^{3} }

<u><em>El peso especifico es 7749.9</em></u>\frac{N}{m^{3} }<u><em></em></u>

8 0
3 years ago
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