Other group because they weren’t in the right group
A) 4
pH=-log[H+]
pH=-log(10^-4)
B) Weaker
pH of orange juice=4
pH of coffee=5
An acid with pH of 4 is stronger than a pH of 5
C) 7, neither/neutral
pH of water=7
To determine the mass of xenon tetrafluoride, we need to know first the number of fluorine atoms present in <span>oxygen difluoride. We need to convert first the mass into moles then make use of the relation of the elements from the chemical formula. Then, use the avogadro's number to convert it to number of atoms. Then, we do the reverse of the steps above but this time for </span><span>xenon tetrafluoride.
25.0 g OF2 ( 1 mol / 54 g ) ( 2 mol F / 1 mol OF2 ) ( 6.022 x10^23 atoms F / 1 mol F ) ( 1 mol / 6.022x10^23 atoms) ( 1 mol XeF4 / 4 mol F ) (207.3 g / 1 mol XeF4) = 47.99 g XeF4</span>
Answer:
C = through filter
Explanation:
If the particle size is is greater than 1000 nm then particles can be separated through the filtration. These particles are large enough and can be seen through naked eye.
If the particles size is between 1 - 1000 nm i.e, 0.001- 1μm then it can not be separated through filtration. The pore size of filter paper is 2μm and particles pas through it. However it can be separated through the ultra filtration. In ultra filtration the pore size is reduced by soaking the filter paper in gelatin and then in formaldehyde. This is only in case of when solid colloidal is present, if colloid is liquid , there is no solid particles present and ultra filtration can not be used in this case.
1) 55Fe has 29 neutrons, 58Fe has 31 neutrons (difference of three neutrons).
2)The configuration is incorrect for both of these reasons.
