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iogann1982 [59]

2 years ago

5

When solute particles are added to a pure solvent in a closed container at a constant temperature and pressure, the vapor pressu

re _________.

1 answer:

ELEN [110]2 years ago

5 0

Answer:

Decreases

Explanation:

Hope this helps:) Good luck!

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Why do the Noble gases have the highest ionization energies across a period?

Kitty [74]

Answer:

ionization energy decreases from top to bottom in groups, and increases from left to right across a period. So technically, the noble games have the largest ionization energy.

Explanation:

3 0

3 years ago

8. A polar covalent bond is due to: unequal sharing of electrons in a covalent bond. the interaction between an ion and a non-io

Zolol [24]

Answer:

The appropriate option will be Option A (unequal sharing of electrons in a covalent bond).

Explanation:

A polar bond seems to be a covalent bond amongst two or even more atoms where there is an uneven distribution of the electrons surrounding the connection.
This induces a small electrical magnetic dipole in the molecules whereby the end becomes generally favorable and another is mildly controversial.

The other choices aren't relevant to the situation presented. The answer above would be appropriate.

4 0

4 years ago

The copper(I) ion forms a chloride salt (CuCl) that has Ksp = 1.2 x 10-6. Copper(I) also forms a complex ion with Cl-:Cu+ (aq) +

Mnenie [13.5K]

Answer: (a) The solubility of CuCl in pure water is $1.1 \times 10^{-3} M$ .

(b) The solubility of CuCl in 0.1 M NaCl is $9.5 \times 10^{-3} M$ .

Explanation:

(a) Chemical equation for the given reaction in pure water is as follows.

$CuCl(s) \rightarrow Cu^{+}(aq) + Cl^{-}(aq)$

Initial: 0 0

Change: +x +x

Equilibm: x x

$K_{sp} = 1.2 \times 10^{-6}$

And, equilibrium expression is as follows.

$K_{sp} = [Cu^{+}][Cl^{-}]$

$1.2 \times 10^{-6} = x \times x$

x = $1.1 \times 10^{-3} M$

Hence, the solubility of CuCl in pure water is $1.1 \times 10^{-3} M$ .

(b) When NaCl is 0.1 M,

$CuCl(s) \rightarrow Cu^{+}(aq) + Cl^{-}(aq)$ , $K_{sp} = 1.2 \times 10^{-6}$

$Cu^{+}(aq) + 2Cl^{-}(aq) \rightleftharpoons CuCl_{2}(aq)$ , $K = 8.7 \times 10^{4}$

Net equation: $CuCl(s) + Cl^{-}(aq) \rightarrow CuCl_{2}(aq)$

$K' = K_{sp} \times K$

= 0.1044

So for, $CuCl(s) + Cl^{-}(aq) \rightarrow CuCl_{2}(aq)$

Initial: 0.1 0

Change: -x +x

Equilibm: 0.1 - x x

Now, the equilibrium expression is as follows.

K' = $\frac{CuCl_{2}}{Cl^{-}}$

0.1044 = $\frac{x}{0.1 - x}$

x = $9.5 \times 10^{-3} M$

Therefore, the solubility of CuCl in 0.1 M NaCl is $9.5 \times 10^{-3} M$ .

7 0

3 years ago

Describe the basic characteristics of each group of elements on the periodic table

Fofino [41]

Answer:

Characteristics of Group

Explanation:

The elements of a group show similar chemical properties but there is a gradual variation in the physical properties of the elements in a group.

8 0

3 years ago

What does lithium 6 and lithium 7 look like

Marysya12 [62]

Lithium 6 would have 6 valence electrons in the outer orbital, while lithium 7 would have 7 in the outer orbital.

3 0

3 years ago