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-Dominant- [34]
2 years ago
10

Wave travelling along right with speed of 0. 5 m/s time 4 second point p

Physics
1 answer:
Soloha48 [4]2 years ago
5 0

The wavelength of the wave which is travelling along right with speed of 0. 5 m/s time 4 second point is 2.

<h3>What is the speed of wave?</h3>

Speed of wave is the rate by which the wave travels. It can be described as the distance cover by the crest or thrust of it per unit of time. It can be calculated with the following formula,

v=f\times\lambda

Here, (f) is the frequency and (λ) is the wavelength.

The frequency is inverse of time. Thus, the value of frequency in time t is,

f=\dfrac{1}{t}\\f=\dfrac{1}{4}\\f=0.25

The speed of the wave is 0.5 m/s. Put the values in the formula,

v=f\times\lambda\\0.5=0.25\times\lambda\\\lambda=\dfrac{0.5}{0.25}\\\lambda=2

Thus, the wavelength of the wave which is travelling along right with speed of 0. 5 m/s time 4 second point is 2.

Learn more about the speed of wave here;

brainly.com/question/12215474

#SPJ4

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The observable universe is still huge, but it has limits. because it's most likely like an plane all round.

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The answer would be erin out of all of them thank me later :)
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3 years ago
Classify the waves as longitudinal or transverse.
tresset_1 [31]

Answer:

1. transverse

2. transverse

3. longitudinal

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Explanation:

8 0
3 years ago
Debido al desorden en el laboratorio un científico tiene 2 termómetros diferentes pero no sabe en qué escalas están por lo que d
just olya [345]

Answer:

La escala del termómetro ''A'' es grados Celsius.

La escala del termómetro ''B'' es grados Fahrenheit.

Explanation:

Para hallar en qué escalas están los termómetros partimos de que la mezcla a la cuál se midió su temperatura mantuvo su temperatura constante.

Esto quiere decir que los termómetros están expresando la misma temperatura pero en una escala distinta.

Sabemos que dada una temperatura en grados Celsius ''C'' si la queremos convertir a grados Fahrenheit ''F'' debemos utilizar la siguiente ecuación :

F=(\frac{9}{5})C+32 (I)

Ahora, si reemplazamos y asumimos que la temperatura de 18° es en grados Celsius, entonces si reemplazamos C=18 en la ecuación (I) deberíamos obtener F=64.4 ⇒

F=(\frac{9}{5}).(18)+32=32.4+32=64.4

Efectivamente obtenemos el valor esperado. Finalmente, corroboramos que la temperatura del termómetro ''A'' está medida en grados Celsius y la temperatura del termómetro ''B'' en grados Fahrenheit.

6 0
3 years ago
An open organ pipe of length 0.47328 m and another pipe closed at one end of length 0.702821 m are sounded together. What beat f
sineoko [7]

Answer:

fb = 240.35 Hz

Explanation:

In order to calculate the beat frequency generated by the first modes of each, organ and tube, you use the following formulas for the fundamental frequencies.

Open tube:

f=\frac{v_s}{2L}         (1)

vs: speed of sound = 343m/s

L: length of the open tube = 0.47328m

You replace in the equation (1):

f=\frac{343m/s}{2(0.47228m)}=362.36Hz      

Closed tube:

f'=\frac{v_s}{4L'}

L': length of the closed tube = 0.702821m

f'=\frac{343m/s}{4(0.702821m)}=122.00Hz

Next, you use the following formula for the beat frequency:

f_b=|f-f'|=|362.36Hz-122.00Hz|=240.35Hz

The beat frequency generated by the first overtone pf the closed pipe and the fundamental of the open pipe is 240.35Hz

7 0
3 years ago
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