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2 years ago

Wave travelling along right with speed of 0. 5 m/s time 4 second point p

1 answer:

5 0

The wavelength of the wave which is travelling along right with speed of 0. 5 m/s time 4 second point is 2.

<h3>What is the speed of wave?</h3>

Speed of wave is the rate by which the wave travels. It can be described as the distance cover by the crest or thrust of it per unit of time. It can be calculated with the following formula,

$v=f\times\lambda$

Here, (f) is the frequency and (λ) is the wavelength.

The frequency is inverse of time. Thus, the value of frequency in time t is,

$f=\dfrac{1}{t}\\f=\dfrac{1}{4}\\f=0.25$

The speed of the wave is 0.5 m/s. Put the values in the formula,

$v=f\times\lambda\\0.5=0.25\times\lambda\\\lambda=\dfrac{0.5}{0.25}\\\lambda=2$

Thus, the wavelength of the wave which is travelling along right with speed of 0. 5 m/s time 4 second point is 2.

Learn more about the speed of wave here;

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A 4.0kg block is sliding with a constant velocity of 3.0m/s on a frictionless table that is 0.5m high. If all of the block’s ene

MArishka [77]

Answer:

Velocity = 4.33[m/s]

Explanation:

The total energy or mechanical energy is the sum of the potential energy plus the kinetic energy, as it is known the velocity and the height, we can determine the total energy.

$E_{M}=E_{p} + E_{k} \\E_{p} = potential energy [J]\\E_{k} = kinetic energy [J]\\where:\\E_{p} =m*g*h\\E_{p} = 4*9.81*0.5=19.62[J]\\E_{k}=\frac{1}{2} *m*v^{2} \\E_{k}=\frac{1}{2} *4*(3)^{2} \\E_{k}=18[J]\\Therefore\\E_{M} =18+19.62\\E_{M}=37.62[J]$

All this energy will become kinetic energy and we can find the velocity.

$37.62=\frac{1}{2} *m*v^{2} \\v=\sqrt{\frac{37.62*2}{4} } \\v=4.33[m/s]$

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3 years ago

How does chemical energy hold molecules together?

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Chemical energy holds molecules together by forming the bonds between atoms. the form of electric bonds.

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3 years ago

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michael kicks a ball at an angle if 36* horizontal. its initial velocity is 46 m/s. Find the maximum height it can reach, total

MAVERICK [17]

(a) At its maximum height, the ball's vertical velocity is 0. Recall that

${v_y}^2-{v_{0y}}^2=2a_y\Delta y$

Then at the maximum height $\Delta y=y_{\mathrm{max}}$ , we have

$-\left(\left(46\,\dfrac{\mathrm m}{\mathrm s}\right)\sin36^\circ\right)^2=2\left(-9.8\,\dfrac{\mathrm m}{\mathrm s^2}\right)y_{\mathrm{max}}$

$\implies y_{\mathrm{max}}=37\,\mathrm m$

(b) The time the ball spends in the air is twice the time it takes for the ball to reach its maximum height. The ball's vertical velocity is

$v_y=v_{0y}+a_yt$

and at its maximum height, $v_y=0$ so that

$0=\left(46\,\dfrac{\mathrm m}{\mathrm s}\right)\sin36^\circ+\left(-9.8\,\dfrac{\mathrm m}{\mathrm s}\right)t$

$\implies t=2.8\,\mathrm s$

which would mean the ball spends a total of about 5.6 seconds in the air.

$x=v_{0x}t$

so that after 5.6 seconds, it will have traversed a displacement of

$x=\left(46\,\dfrac{\mathrm m}{\mathrm s}\right)\cos36^\circ(5.6\,\mathrm s)$

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3 years ago

PLEASE HELP WILL GIVE BRAINLIEST AND EXTRA POINTS!! Super simple I’ve just been sick so I have no clue what’s going on.

Tju [1.3M]

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Explanation:

12) Conservation of momentum. Momentum is the produce of mass and velocity.

13(2) + 15(-5) = 13(-5) + 15v

v = 1.06666... ≈ 1.07 m/s (right)

13) 18(9) + 22(0) = 18v + 22v

v = 18(9)/40 = 4.05 m/s

14) 0.65(35) + 0.08(0) = 0.65(26) + 0.08v

v = 73.125

15) This is a bit trickier. Let's ASSUME you jump off at 7 m/s relative to the truck. Doing this, we can assume that the reference frame is moving along with the truck at 10 m/s

the conservation of momentum equation becomes

600(0) + 80(0) = 600v + 80(-7)

v = 0.9333333... m/s

adding back the velocity of the reference frame means the truck is now traveling.

10.9333333... ≈ 10.9 m/s

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3 years ago

Electric charge can be transferred from one conducting body to another _________. View Available Hint(s)for Part A only by conta

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Answer:

by both contact and closeness

Explanation:

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2 years ago