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-Dominant- [34]
2 years ago
10

Wave travelling along right with speed of 0. 5 m/s time 4 second point p

Physics
1 answer:
Soloha48 [4]2 years ago
5 0

The wavelength of the wave which is travelling along right with speed of 0. 5 m/s time 4 second point is 2.

<h3>What is the speed of wave?</h3>

Speed of wave is the rate by which the wave travels. It can be described as the distance cover by the crest or thrust of it per unit of time. It can be calculated with the following formula,

v=f\times\lambda

Here, (f) is the frequency and (λ) is the wavelength.

The frequency is inverse of time. Thus, the value of frequency in time t is,

f=\dfrac{1}{t}\\f=\dfrac{1}{4}\\f=0.25

The speed of the wave is 0.5 m/s. Put the values in the formula,

v=f\times\lambda\\0.5=0.25\times\lambda\\\lambda=\dfrac{0.5}{0.25}\\\lambda=2

Thus, the wavelength of the wave which is travelling along right with speed of 0. 5 m/s time 4 second point is 2.

Learn more about the speed of wave here;

brainly.com/question/12215474

#SPJ4

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A bird is about 6.26.2 in.​ long, with a​ thin, dark bill and a​ wide, white wing stripe. If the bird can fly 9292 mi with the w
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209 mph

Explanation:

V = Speed of bird in still air

v = Speed of wind = 44 mph

Consider the motion of the bird with the wind

D_{1} = distance traveled with the wind = 9292 mi

t_{1} = time taken to travel the distance with wind

Time taken to travel the distance with wind is given as

t_{1} = \frac{D_{1}}{V + v}

t_{1} = \frac{9292}{V + 44}                              eq-1

Consider the motion of the bird with the wind

D_{2} = distance traveled against the wind = 6060 mi

t_{2} = time taken to travel the distance against wind

Time taken to travel the distance against wind is given as

t_{2} = \frac{D_{2}}{V + v}

t_{2} = \frac{6060}{V - 44}                              eq-2

As per the question,

Time taken with the wind = Time taken against the wind

t_{1} = t_{2}

\frac{9292}{V + 44} = \frac{6060}{V - 44}

(9292) (V - 44) = (6060) (V + 44)

9292V - 408848 = 6060V + 266640

3232V = 675488

V = 209 mph

5 0
3 years ago
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