From tables, the density of mercury is
13545 kg/m^3 at 20°C,
13472 kg/m^3 at 50°C.
Because mass = density * volume, the mass of mercury at 20°C is
m = (13545 kg/m^3)*(0.002 m^3) = 27.09 kg
Let V = volume of mercury at 50°C.
Because the mass of mercury does not change, therefore at 50°C,
(13472 kg/m^3)*(V m^3) = 27.09
V = 27.09/13472 = 0.0020108 m^3
Answer: B. 0.002010812 m³
Answer:
if the old force is F, the new force is F/9
Explanation:
Recall that the Coulomb force between to charges is inversely proportional to the square of the distance between the charges.
Therefore, if the original distance "d" changes now to be "3d" (tripled), the denominator of the force expression will change from:

thus reducing the original force by a factor 1/9
So if the old force is F, the new force is F/9
Answer:
The speed of water flow inside the pipe at point - 2 = 34.67 m / sec
Explanation:
Given data
Diameter at point - 1 = 3.2 cm
Velocity at point - 1 = 1.1 m / sec = 110 cm / sec
Diameter at point - 2 = 0.57 cm
Velocity at point - 2 = ??
We know that from the continuity equation the rate of flow is constant inside a pipe between two points.
Thus
⇒
×
=
× 
⇒
×
×
=
⇒
×
=
× 
⇒
× 110 =
× 
⇒
= 3467 cm / sec
⇒
= 34.67 m / sec
Thus the speed of water flow inside the pipe at point - 2 = 34.67 m / sec
The answer C. 2p. I took the quiz and I got it correct.
Assume theres no air reaistance. (or else the ball will oppose the motion of the ball, hence decrease the velocity increase)
see if there are any problems!