Answer:
The Phases of Matter are Solid, Liquid, and Gas. With Plasma as an exception. Solids are defined by their structural stiffness and resistance to form or volume changes. A liquid is a compressible fluid is one that adapts to the geometry of its container while maintaining a consistent volume regardless of pressure. Gas compresses easily, expands to fill containers, and takes up significantly more space than the liquids or solids from which it is formed. Plasma has no fixed shape or solid volume just like gas. That's the best I can explain, hope you find it helpful!
Explanation:
Answer:
26.20% w/w of KBr in the sample
Explanation:
Mohr titration is a way to quantify Br⁻ and Cl⁻ ions in solution. The reaction is:
KBr(aq) + AgNO₃(aq) → KNO₃(aq) + AgBr(s)
<em>where 1 mole of KBr reacts per mole of AgNO₃</em>
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Thus, moles of AgNO₃ in (25.13mL-0.65mL = 24.48mL) of a 0.04614M solution are:
0.02448L × (0.04614mol / L) = 1.130x10⁻³ moles of AgNO₃ = moles of KBr.
Mass of KBr -Molar mass: 119g/mol- is:
1.130x10⁻³ moles of KBr × (119g / 1mol) = <em>0.1344g of KBr</em>
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Thus, %w/w of KBr in the sample is:
%w/w = 0.1344g / 0.5131g ×100 = <em>26.20% w/w of KBr in the sample</em>
The table with the data is in the picture attached.
Answer:
Explanation:
The reaction equation suggests that the law could have this form:
Then, the work is to find the values of the exponents that satisfy the initial rate data.
A first glance shows that for the third and fourth trials the initial rates are the same. Since for these two trials only the initial concentration of substance B changed (A and C were kept equal), you conclude that the reaction rate does not depend on B, and ist exponent (lower b) is 0.
Then, so far you can say:
When you use trials 1 and 2, you get:
Now, you can use trials 1 and 3 to determine the other exponent:
Thus, you have the rate law:
Now, you just use any trial to obtain k. Using trail 1:
Which yields:
How does the law of conservation of mass apply to this reaction: C2H4 + O2 → H2O + CO2?
Answer: 27 grams of Be
Explanation: Berylium has a molar mass of 9.0 grams/mole
(9.0 grams/mole)*(3 moles Be) = 27 grams Be