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GenaCL600 [577]

2 years ago

13

A periodic wave has a fixed pattern that is repeated. what is one completion of the wave pattern called? a. equilibrium b. frequ

ency c. amplitude d. cycle e. phase

1 answer:

Veronika [31]2 years ago

3 0

Answer:

D.

Explanation:

cycle.

I think it’s a cycle because a wave pattern is kind of like a type of cycle because it happens over and over again.

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The "zone of avoidance" a) Accounts for the absence of any planet between the orbits of Mars and Jupiter Prevents collisions bet

shusha [124]

Answer:

b) obscures visual observation through the plane of the Milky Way.

Explanation:

The "zone of avoidance"

Avoidance zone, an area characterized by an apparent lack of galaxies near the Milky Way Galaxy plane and caused by the mysterious impact of interstellar dust. The zone of avoidance is completely a local Milky Way Galaxy effect.

The correct answer is

b) obscures visual observation through the plane of the Milky Way.

7 0

3 years ago

Acceleration due to gravity on the moon is 1.6m/s^2 or about 16% of the value of gg on Earth. If an astronaut on the moon threw

xxTIMURxx [149]

To solve this problem it is necessary to apply the concepts related to the conservation of Energy. Mathematically the conservation of kinetic energy must be paid in the increase of potential energy or vice versa. This expressed in algebraic terms is equivalent to

Kinetic Energy = Potential Energy

$\frac{1}{2}mv^2 = mgh$

Where

m = Mass

v = Velocity

g = Gravity

h = Height

As the mass is the same then we have to

$\frac{1}{2} v^2 = gh$

Rearrange to find v,

$v = \sqrt{2gh}$

Our values are given as

$g = 1.6m/s^2$

$h = 7.8m$

Therefore replacing we have

$v = \sqrt{2(1.6)(7.8)}$

$v = 4.99m/s$

Hence the velocity at the moon would be 4.99m/s

The only direct affectation is that concerning the Resistance or drag force generated by a fluid - such as air in the ground - that can diminish / sharpen the direct effects of gravity. Disregarding the resistance of the air, as we can see in the equation previously given, there should be no affectation because the speed depends on the gravity and height.

5 0

4 years ago

Which ocean borders the west coast of this United States

Gennadij [26K]

The Pacific.
Hope it helps!

3 0

4 years ago

When a brick is dropped from the roof of a house, it lands on the ground with a speed v. What will the speed at ground level be

Nina [5.8K]

Twice as much by the first brick

4 0

3 years ago

A 0.750 kg block is attached to a spring with spring constant 17.5 N/m. While the block is sitting at rest, a student hits it wi

Dmitriy789 [7]

Answer:

a

$A = 0.081 \ m$

b

The value is $u = 0.2569 \ m/s$

Explanation:

From the question we are told that

The mass is $m = 0.750 \ kg$

The spring constant is $k = 17.5 \ N/m$

The instantaneous speed is $v = 39.0 \ cm/s= 0.39 \ m/s$

The position consider is x = 0.750A meters from equilibrium point

Generally from the law of energy conservation we have that

The kinetic energy induced by the hammer = The energy stored in the spring

So

$\frac{1}{2} * m * v^2 = \frac{1}{2} * k * A^2$

Here a is the amplitude of the subsequent oscillations

=> $A = \sqrt{\frac{m * v^ 2 }{ k} }$

=> $A = \sqrt{\frac{0.750 * 0.39 ^ 2 }{17.5} }$

=> $A = 0.081 \ m$

Generally from the law of energy conservation we have that

The kinetic energy by the hammer = The energy stored in the spring at the point considered + The kinetic energy at the considered point

$\frac{1}{2} * m * v^2 = \frac{1}{2} * k x^2 + \frac{1}{2} * m * u^2$

=> $\frac{1}{2} * 0.750 * 0.39^2 = \frac{1}{2} * 17.5* 0.750(0.081 )^2 + \frac{1}{2} * 0.750 * u^2$

=> $u = 0.2569 \ m/s$

3 0

3 years ago