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2 years ago

Wich statement correctly relates science and its influence on society

Chemistry

2 answers:

balandron [24]2 years ago

8 0

Which statement correctly relates science and its influence on society?

Answer:

The statement that correctly relates science and its influence on society is the following: Science can solve societal problems, and it can affect societal decisions.

<span>I hope it helps, Regards. </span>

Rudiy272 years ago

4 0

The statement that correctly relates science and its influence on society is : Science can be used to address societal problems, but it is not always successful

for example, science can be used to address food shortage. Through various biotechnology, society doesn't have to be worry about food shortage in the future

hope this helps<span />

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What is the name of The compound?

Liono4ka [1.6K]

Answer:

But-2-ene is your answer i guess

5 0

2 years ago

A person suffering from hyponatremia has a sodium ion concentration in the blood of 0.116 M and a total blood volume of 4.7 L .

klemol [59]

Explanation:

Normal moles of $Na^{+}$ = volume × normal concentration

= 4.7 × 0.139 = 0.6533 mol

Moles of $Na^{+}$ in hyponatremia blood = volume × hyponatremia concentration

= 4.7 × 0.116 = 0.5452 mol

Moles of NaCl to be added = moles of extra $Na^{+}$ needed

= 0.6533 mol - 0.5452 mol = 0.1081 mol

Mass of NaCl = moles × molar mass of NaCl

= 0.1081 mol × 58.443

= 6.317g

= 6.32 g (approx)

Thus, we can conclude that mass of sodium chloride would need to be added to the blood is 6.32 g.

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2 years ago

When 1.045 g of CaO is added to 50.0 mL of water at 25.0 °C in a calorimeter, the temperature of the water increases to 32.3 °C.

Rus_ich [418]

Answer:

1.71 kJ/mol

Explanation:

The expression for the calculation of the enthalpy change of a process is shown below as:-

$\Delta H=m\times C\times \Delta T$

Where,

$\Delta H$ is the enthalpy change

m is the mass

C is the specific heat capacity

$\Delta T$ is the temperature change

Thus, given that:-

Mass of CaO = 1.045 g

Specific heat = 4.18 J/g°C

$\Delta T=32.3-25.0\ ^0C=7.3\ ^0C$

So,

$\Delta H=1.045\times 4.18\times 7.3\ J=31.88713\ J$

Also, 1 J = 0.001 kJ

So,

$\Delta H=0.03189\ kJ$

Also, Molar mass of CaO = 56.0774 g/mol

$Moles=\frac{Mass}{Molar\ mass}=\frac{1.045}{56.0774}\ mol=0.01863\ mol$

Thus, Enthalpy change in kJ/mol is:-

$\Delta H=\frac{0.03189}{0.01863}\ kJ/mol=1.71\ kJ/mol$

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2 years ago

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77julia77 [94]

Answer:

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2 years ago

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Sedbober [7]

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2 years ago