All categories

3 years ago

Wich statement correctly relates science and its influence on society

Chemistry

2 answers:

balandron [24]3 years ago

8 0

Which statement correctly relates science and its influence on society?

Answer:

The statement that correctly relates science and its influence on society is the following: Science can solve societal problems, and it can affect societal decisions.

<span>I hope it helps, Regards. </span>

Rudiy273 years ago

4 0

The statement that correctly relates science and its influence on society is : Science can be used to address societal problems, but it is not always successful

for example, science can be used to address food shortage. Through various biotechnology, society doesn't have to be worry about food shortage in the future

hope this helps<span />

You might be interested in

N2+3H2 → 2NH3

s2008m [1.1K]

Explanation:

N2 (g) + H2 (g) gives out NH3 (g)

Now balance it. You have two reactants with compositions involving a single element, which makes it very easy to keep track of how much is on each side. I would balance the nitrogens, and then the hydrogens.(If you balance the hydrogen reactant with a whole number first, I can guarantee you that you will have to give NH3 a new stoichiometric coefficient.)

N2 (g) + 3H2 (g) gives out 2NH3 (g)

The stoichiometric coefficients tell you that if we can somehow treat every component in the reaction as the same (like on a per-mol basis, hinthint), then one "[molar] equivalent" of nitrogen yields two [molar] equivalents of ammonia.

Luckily, one mol of anything is equal in quantity to one mol of anything else because the comparison is made in the units of mols.

So what do we do? Convert to

mols (remember the hint?).

28g N2 × 1 mol N2/ 2 × 14.007) g N2

= 0.9995 mol N2

At this point you don't even need to calculate the number of mols of H2 . Why? Because H2 is about 2 g/mol, which means we have over 10 mols of H2. We have 1 mol N2, and we need three times as many mols of H2 as we have

N2.

After doing the actual calculation you should realize that we have about 4 times as much H2 as we need. Therefore the limiting reagent is clearly N2.

Thus, we should yield 2×0.9995=1.9990 mols of NH3 (refer back to the reaction). So this is the second and last calculation we need to do:

1.9990 mol NH3 × 17.0307 g NH3/ 1 mol NH3

= 34.0444 g NH3

Hope it helpz~

4 0

2 years ago

A Helium gas in a tube with a volume of 9.583 L under pressure of 4.972 atm at 31.8 c

andre [41]

1.905 moles of Helium gas are in the tube. Hence, option A is correct.

<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

Calculate the moles of the gas using the gas law,

PV=nRT, where n is the moles and R is the gas constant. Then divide the given mass by the number of moles to get molar mass.

Given data:

P= 4.972 atm

V= 9.583 L

n=?

R= $0.082057338 \;L \;atm \;K^{-1}mol^{-1}$

T=31.8 +273= 304.8 K

Putting value in the given equation:

$\frac{PV}{RT}$ =n

n= $\frac{4.972 \;atm\; X \;9.583 \;L}{0.082057338 \;L \;atm \;K^{-1}mol^{-1} X 304.8}$

Moles = 1.905 moles

1.905 moles of Helium gas are in the tube. Hence, option A is correct.

Learn more about the ideal gas here:

brainly.com/question/27691721

#SPJ1

3 0

2 years ago

To convert measurements in the metric system you can move the decimal point left or right why does this work?

Serhud [2]

Explanation:

Because when you move the decimal point once, it it equal to 10 and to convert in the metric system, you must multiply or divide by 10. For example, when converting 4 centimeters to millimeters, you can multiply by 10 to get 40 millimeters or you can move the decimal point to the right and add another 0 to get 40.

3 0

2 years ago

Which of the following are physical properties of nonmentals

coldgirl [10]

You did not provide any options.

6 0

2 years ago

The molar mass of a certain gas is 80.6 g. What is the density of the gas in g/L at STP?

vfiekz [6]

Using the ideal gas equation:
PV = nRT

Substituting n with mass / Mr
PV = mRT/Mr

Density = m/V
So rearranging:
Density = PMr/RT

P = 1 atm
R = 0.082 L atm / K mol
T = 273 K
Density = (1 x 80.6) / (0.082 x 273)
Density = 3.6 g / L

3 0

3 years ago