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zloy xaker [14]

1 year ago

8

When all wavelengths of the visible light spectrum are present, the color is seen. _ is seen when all wavel

engths of light are absent.
a.
black, white
c.
grey, brown
b.
white, black
d.
None of the above.

1 answer:

allochka39001 [22]1 year ago

7 0

B. White and black are the answers.

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Can someone help me ASAP on this science question

Art [367]

D because 15 kg weighs less and therefore it will result in the greatest change in speed

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What is potential energy ?

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Answer: it’s when Somethisomething is at the High Point like the top of the roller coaster or the top of the hill I will add a photo to explain

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2 years ago

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As an acapulco cliff diver drops to the water from a height of 42.0 m, his gravitational potential energy decreases by 27,500 j.

seraphim [82]

We know that potential energy is simply energy due to position which has the formula:

PE = mass * gravity * height

We know that mass * gravity is weight, therefore:

PE = weight * height

27500 J = weight * 42 m

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3 years ago

A force of 500 N is used to slide a box across a smooth surface; the box moved 5 m in 1.2 seconds. What power is used?

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F = 500N
S = 5m
T = 1.2s
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P = ?

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So the final answer would be:

P = F * V = 500 * 50/12

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3 years ago

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In a ballistic pendulum experiment, projectile 1 results in a maximum height h of the pendulum equal to 2.6 cm. A second project

Trava [24]

Answer:

Second projectile is 1.4 times faster than first projectile.

Explanation:

By linear momentum conservation

Pi = Pf

m x U + M x 0 = (m + M) x V

$U= \dfrac{(m + M)\times V}{m}$

Now Since this projectile + pendulum system rises to height 'h', So using energy conservation:

KEi + PEi = KEf + PEf

PEi = 0, at reference point

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$KEi = \dfrac{(m + M)\times V^2}{2}$

PEf = (m + M) g h

So,

$\dfrac{(m + M)\times V^2}{2} + 0 = 0+ (m + M) g h$

$V =\sqrt {2gh}$

So from above value of V

Initial velocity of projectile =U

$U=\dfrac{(M+m)\sqrt{2gh}}{m}$

Now Since mass of projectile and pendulum are constant, So Initial velocity of projectile is proportional to the square root of height swung by pendulum.

Which means

$\dfrac{U_2}{U_1}=\sqrt{\dfrac{h_2}{h_1}}$

$U_2=\sqrt{\dfrac{h_2}{h_1}}\times U_1$

$U_2=\sqrt{\dfrac{5.2}{2.6}}\times U_1$

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Therefore we can say that ,Second projectile is 1.4 times faster than first projectile.

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2 years ago