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riadik2000 [5.3K]
2 years ago
8

In the "monster study," what did psychologists tell the group of orphans who did not suffer from stuttering? a. they were told t

hat they weren’t really stutterers. b. they were told that they had very severe cases of stuttering. c. they were told that stuttering could be overcome with practice. d. they were told that their parents were responsible for their stuttering.
Physics
2 answers:
aniked [119]2 years ago
8 0

In the "monster study", psychologists told to orphans that they had very severe cases of stuttering (Option B).

<h3>What was the monster study?</h3>

The monster study was a psychology analysis developed by Wendell Johnson to understand why there were 22 orphans who develop a stutter.

  • The monster study has been considered unethical because it violated many different ethical subject matters.

In conclusion, in the "monster study", psychologists told to orphans that they had very severe cases of stuttering (Option B).

Learn more on the monster study here:

brainly.com/question/18330285

#SPJ4

Ronch [10]2 years ago
6 0

Answer:

B. They were told that they had very severe cases of stuttering.

Explanation:

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Answer:

B

Explanation:

This happens because adding salt to the water decreases Its density. When the density of the water matches that of the egg, the egg becomes neutrally buoyant and floats.

The weight of the egg becomes equal to the upward buoyant force by the water on to the egg and hence, the egg floats.

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How big is the planet earth​
AnnZ [28]

After doing some research on Wiki, Google, and Easyscienceforkids, I have come to a conclusion that:

Mass: 5.972 * 10^24 kg

Radius: 3958.8 mi

Distance from the sun: 92.96 million mi

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3 years ago
A doubly ionized molecule (i.e., a molecule lacking two electrons) moving in a magnetic field experiences a magnetic force of 5.
Kobotan [32]

Explanation:

The given data is as follows.

           F = 5.75 \times 10^{-16} N

          q = 1.6 \times 10^{-19} C

          v = 385 m/s

       sin (63.9^{o}) = 0.876

Now, we will calculate the magnitude of magnetic field as follows.

              B = \frac{F}{qv sin (\theta)}

                  = \frac{5.75 \times 10^{-16} N}{1.6 \times 10^{-19} C \times 385 m/s \times 0.876}

                  = 0.01065 \times 10^{3} T

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4 0
3 years ago
Check the correctness of formula t=2π √m/k, dimensionally​
pantera1 [17]

Hi there! Lets see!

  • m is mass, and its units are kg
  • k is the elastic constant measured in newtons per meter (N/m), or kilograms per second squared kg/s²

Therefore:

\sqrt{\dfrac{m}{k}} =\sqrt{\dfrac{[kg]}{[\dfrac{kg}{s^2}]}}  =\sqrt{\dfrac{[kg]}{[kg]}\cdot s^2} = \sqrt{[s]^2} = s

The period is given in seconds so the formula is dimensionally​ correct.

4 0
3 years ago
Steam enters an adiabatic turbine at 6 MPa, 600 ℃, and 80 m/s and leaves at 50 kPa, 100 ℃, and 140 m/s. If the power output of t
lisabon 2012 [21]

Answer:

W(r,out) = 5.81 MW

\eta = 86.1 %

Explanation:

we use here steam table for get value of h1, s1 etc

so use for 6MPa and 600 degree

Enthalphy of steam h1 = 3658.8 kJ/kg

Entropy of steam s 1 is = 7.1693 kJ /kg.K

and

for 50 kPa and 100 degree

Enthalphy of steam h2 = 2682.4 kJ/kg

Entropy of steam s2 is = 7.6953 kJ /kg.K

so we use here energy balance equation that is

m\times(h1 + \frac{v1^2}{2} = m\times(h2 + \frac{v2^2}{2} + W(out)      ..............1

put here value and we get m

m = \frac{5\times1000}{3658.8-2682.4+\frac{80^2-140^2}{2}\times \frac{1}{1000}}  

solve it we get

m = 5.156 kg/s

so by energy balance equation

m\psi1 = m\psi2 + W(r,out)

W(r,out) = m(\psi1 -\psi2)

W(r,out) = h1 - h2 + ΔKE + ΔPE - To(s1-s2)

W(r,out) = m[h1-h2+ \frac{v1^2-v^2}{2}- To (s1-s2)

W(r,out) = W(a,out) - m.To.(s1-s2)     ........................2

put here value

W(r,out) = 5000 - ( 5.156 × (25 + 273) ×( 7.1693 - 7.6953)

W(r,out) = 5908.19 = 5.81 MW

and

second law deficiency is

\eta = \frac{W(a,out)}{W(r,out)}     ..............................3

put here value

\eta = \frac{5}{5.81}

\eta = 86.1 %

6 0
3 years ago
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