The ball rolls off the table with speed <em>v</em> from a height of 0.35 m, so that it covers a horizontal distance <em>x</em> with height <em>y</em> at time <em>t</em> of
<em>x</em> = <em>v t</em>
<em>y</em> = 0.35 m - 1/2 <em>g t</em> ²
where <em>g</em> = 9.80 m/s² is the magnitude of the acceleration due to gravity.
Solve for <em>t</em> when <em>y</em> = 0, i.e. the time it takes for the ball to reach the ground:
0 = 0.35 m - 1/2 <em>g</em> <em>t</em> ²
<em>t</em> ² = (0.70 m) / <em>g</em>
<em>t</em> ≈ 0.267 s
Now solve for <em>v</em> given that the ball falls 3 m away from the table:
3 m = <em>v</em> (0.27 s)
<em>v</em> = (3 m) / (0.27 s)
<em>v</em> ≈ 11.2 m/s
Answer:
two forces are acting in opposite directions on an object, and they are equal in size.
The distance covered by the plane in its accelerated motion is 750 m
Explanation:
The motion of the plane is a uniformly accelerated motion, so we can use the following suvat equation:
where
v is the final velocity
u is the initial velocity
t is the time
s is the displacement
For the plane in this problem,
is the initial velocity
v = 0 (the plane comes to a stop)
t = 30 s
Solving for s, we find the displacement of the plane, which corresponds to the distance covered:
Learn more about accelerated motion:
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Answer:
KE = 10530 J or 10.53 KJ
Explanation:
The formula for kinetic energy is KE = 1/2 mv^2
Let's apply the formula:
KE = 1/2 mv^2
KE = 1/2 (65kg) (18m/s)^2
KE = 10530 J or 10.53 KJ