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AleksandrR [38]

1 year ago

9

Hip hop dance translate feelings and emotions of human conditions, situations, or fantasies into movement and dramatic expressio

ns? True or false?

1 answer:

attashe74 [19]1 year ago

4 0

Answer:

false .....................

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When you set something down on the ground wht kind of work are your arms doing?

umka2103 [35]

When we set something down on the ground, the kind of work that our arms doing is : negative apex
It's happen whenever we do works that are align with the force of Gravity (to the bottom)

hope this helps

7 0

3 years ago

Read 2 more answers

Which of these statements accurately captures a current trend in operations? A. There is increased focus on local market and lo

Flura [38]

Answer:

Option B

Explanation:

The current trend in operations is accurately captured by Rapid Product Development.

This concept in an organization describes a process in development which is quite fast and progressive.

To achieve rapid Product Development, a combination of integration of various innovative and creative prototyping techniques including latest Computer supportive operative tools, i.e., CSCW are used.

These tools are incorporated into the process of Research and Development in an organization in order to develop products by optimization of quality, price and time.

3 0

3 years ago

A 2.4 kg block is dropped onto a spring and platform of negligible mass. The block is released

statuscvo [17]

The speed of the block when the compression is 15 cm is 9.85 m/s.

The given parameters;

<em>mass of the block, m = 2.4 kg</em>
<em>height of the block, h = 5 m</em>
<em>compression of the spring, x = 25 cm = 0.25 m</em>

The spring constant is calculated as follows;

$F = kx\\\\mg = kx\\\\k = \frac{mg}{x} \\\\k = \frac{2.4 \times 9.8}{0.25} \\\\k = 94.08 \ N/m$

The speed of the block when the compression is 15 cm can be determined by applying the principle of conservation of energy;

$\Delta K.E = \Delta P.E\\\\\frac{1}{2} m(v^2 - v_{0 }^2 ) = mgh - \frac{1}{2} kx^2\\\\\frac{1}{2} mv^2 = mgh - \frac{1}{2} kx^2\\\\mv^2 = 2mgh - kx^2\\\\v^2 = \frac{2mgh - kx^2}{m} \\\\v = \sqrt{\frac{2mgh - kx^2}{m}} \\\\v = \sqrt{\frac{(2 \times 2.4 \times 9.8 \times 5) - (94.08 \times 0.15^2)}{2.4}} \\\\v = 9.85 \ m/s$

Thus, the speed of the block when the compression is 15 cm is 9.85 m/s.

Learn more here:brainly.com/question/14289286

8 0

2 years ago

Gravitational attraction depends on the mass of the objects as well as their distance. The gravitational force between objects i

shepuryov [24]

<h2>Answer: Gravitational attraction will be the same</h2>

According to the law of universal gravitation, which is a classical physical law that describes the gravitational interaction between different bodies with mass:

$F=G\frac{m_{1}m_{2}}{r^2}$ (1)

Where:

$F$ is the module of the force exerted between both bodies

$G$ is the universal gravitation constant.

$m_{1}$ and $m_{2}$ are the masses of both bodies.

$r$ is the distance between both bodies

Now, if we double both masses and the distance also doubles, this means:

$m_{1}$ and $m_{2}$ will be now $2m_{1}$ and $2m_{2}$

$r$ will be now $2r$

Let's rewrite the equation (1) with this new values:

$F=G\frac{(2m_{1})(2m_{2})}{(2r)^2}$ (2)

Solving and simplifying:

$F=4G\frac{m_{1}2m_{2}}{4r^2}$

$F=G\frac{m_{1}m_{2}}{r^2}$ (3)

As we can see, equation (3) is the same as equation (1).

So, if the masses both double and the distance also doubles the <u>Gravitational attraction between both masses will remain the same.</u>

7 0

3 years ago

Read 2 more answers

Two speakers both emit sound of frequency 320 Hz, and are in phase. A receiver sits 2.3 m from one speaker, and 2.9 m from the o

satela [25.4K]

Answer:

Option B

Explanation:

The phase difference is found by subtracting the 2.3m for the receiver from the other speaker which is 2.9m hence

Phase difference= 2.9-2.3= 0.6

3 0

2 years ago