Question

If 4.00 moles of fluorine are reacted with excess HBr, how many grams of bromine will be formed

Answer 1

The mass of bromine that would be formed is 639 g

Stoichiometry

From the question,

We are to determine how many grams of bromine would be formed

First, we will write the balanced chemical equation for the reaction,

The balanced chemical equation for the reaction is

F₂ + 2HBr → 2HF + Br₂

This means, 1 mole of fluorine reacts with 2 moles of HBr to produce 1 mole of bromine.

Then,

4.00 moles of fluorine will react with excess HBr to produce 4.00 moles of bromine.

Therefore,

The number of moles of bromine produced is 4.00 moles

Now, for the mass of bromine formed,

Using the formula,

Mass = Number of moles × Molar mass

Molar mass of bromine = 159.808 g/mol

Then,

Mass of bromine formed = 4.00 × 159.808

Mass of bromine formed = 639.232 g

Mass of bromine formed ≅ 639 g

Hence, the mass of bromine that would be formed is 639 g.

Learn more on Stoichiometry here: brainly.com/question/24691353