If 450 grams of dextrose are dissolved in 650ml Of water with a resultant volume of 1 liter what is the percent concentration (w
1 answer:
Considering the definition of mass volume percentage, the percent concentration of dextrose is 45%.
<h3>Mass volume percentage</h3>Mass volume percentage (% m/V) is a measure of concentration that indicates the number of grams of solute per 100 volume units of the solution. In other words, the volume percent of a component in the solution is defined as the ratio of the mass of the component to the volume of the solution, expressed as a percentage.
The mass volume percentage of a solution is determined by the following expression:
In this case, you know:
- mass of solute= 450 grams
- volume of solution= 1 L= 1000 mL
Replacing in the definition of mass volume percentage:
Solving:
<u><em>mass volume percentage= 45%</em></u>
Finally, the percent concentration of dextrose is 45%.
Learn more about mass volume percentage:
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Answer:
Percentage abundance of 121 Sb is = 57.2 %
Percentage abundance of 123 Sb is = 42.8 %
Explanation:
The formula for the calculation of the average atomic mass is:
Given that:
Since the element has only 2 isotopes, so the let the percentage of first be x and the second is 100 -x.
For first isotope, 121 Sb :
% = x %
Mass = 120.9038 u
For second isotope, 123 Sb:
% = 100 - x
Mass = 122.9042 u
Given, Average Mass = 121.7601 u
Thus,
Solving for x, we get that:
x = 57.2 %
<u>Thus, percentage abundance of 121 Sb is = 57.2 % </u>
<u>percentage abundance of 123 Sb is = 100 - 57.2 % = 42.8 %</u>
Answer:
number of hydrogen atom in 1.8 mole of NH2OH =
Explanation:
percentage of hydrogen in NH2OH = mass of hydrogen / mass of whole molecule
=\times 100
= 9.09 percentage
therefore number of moles in 1.8 moles of hydroxy amine =
= .16 moles of hydrogen
number of hydrogen atom = (number of moles )×(avagadro number)
= atoms of hydrogen
Answer: There will be 0.00002 meq per Liter of the solution.
Explanation:
Normality is defined as the umber of gram equivalents dissolved per liter of the solution.
Equivalent weight is calculated by dividing the molecular weight by n factor.
n= charge for charged species , For , n =2
Thus there will be 0.00002 meq per Liter of the solution.