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denpristay [2]
2 years ago
9

If 450 grams of dextrose are dissolved in 650ml Of water with a resultant volume of 1 liter what is the percent concentration (w

/v) of dextrose
Chemistry
1 answer:
krek1111 [17]2 years ago
7 0

Considering the definition of mass volume percentage, the percent concentration of dextrose is 45%.

<h3>Mass volume percentage</h3>

Mass volume percentage (% m/V) is a measure of concentration that indicates the number of grams of solute per 100 volume units of the solution. In other words, the volume percent of a component in the solution is defined as the ratio of the mass of the component to the volume of the solution, expressed as a percentage.

The mass volume percentage of a solution is determined by the following expression:

Mass volume percentage=\frac{mass of solute}{volume of solution}x100

<h3>Percent concentration in this case</h3>

In this case, you know:

  • mass of solute= 450 grams
  • volume of solution= 1 L= 1000 mL

Replacing in the definition of mass volume percentage:

Mass volume percentage=\frac{450 grams}{1000 mL}x100

Solving:

<u><em>mass volume percentage= 45%</em></u>

Finally, the percent concentration of dextrose is 45%.

Learn more about mass volume percentage:

brainly.com/question/14471247

brainly.com/question/18850112

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A 45.0-gram sample of copper metal was heated from 20.0°C to 100.0°C. Calculate the heat absorbed, in kJ, by the metal.
s2008m [1.1K]

Answer:

1.386 KJ

Explanation:

From the question given above, the following data were obtained:

Mass (M) of copper = 45 g

Initial temperature (T1) = 20.0°C

Final temperature (T2) = 100.0°C

Heat absorbed (Q) =..?

Next, we shall determine the change in temperature. This can be obtained as follow:

Initial temperature (T1) = 20.0°C

Final temperature (T2) = 100.0°C

Change in temperature (ΔT) =?

ΔT = T2 – T1

ΔT = 100 – 20

ΔT = 80 °C

Next, we shall determine the heat absorbed by the sample of copper as follow:

Mass (M) of copper = 45 g

Change in temperature (ΔT) = 80 °C

Specific heat capacity (C) of copper = 0.385 J/gºC

Heat absorbed (Q) =..?

Q = MCΔT

Q = 45 × 0.385 × 80

Q = 1386 J

Finally, we shall convert 1386 J to KJ. This can be obtained as follow:

1000 J = 1 KJ

Therefore,

1386 J = 1386 J × 1 KJ /1000 J

1386 J = 1.386 KJ

Thus, the heat absorbed by the sample of the sample of copper is 1.386 KJ.

5 0
2 years ago
A gas occupies 18.5L at stp. what volume will it occupy at 735 torr and 57°c?
olga nikolaevna [1]

 The volume that  will  be occupied at 735  torr and 57 c  is 23.12 L


 <u><em>calculation</em></u>

  • <u><em> </em></u> At STP   temperature=273 k  and  pressure=760 torr
  • <u><em> </em></u>by use of combined  gas formula

that is P1V1/T1= P2V2/T2

where; P1 =760 torr

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     V2= T2P1V1/P2T1

       V2=  [(18.5L  x 330 k  x 760 torr)/(735 torr x 273 k)]= 23.12  L




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