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Alexus [3.1K]
2 years ago
14

In 1927, a little-known Belgian priest named Georges Lemaître was the first to propose an expanding universe, based on Einstein’

s theory of general relativity. Two years later, Edwin Hubble published a scatterplot of recessional velocity vs. galactic distance, shown above in the Velocity-Distance Relationship among Extra-Galactic Nebulae. This was the first observational evidence to support the hypothesis that grew into the Big Bang theory.
Describe how the evidence you have gathered in this Gizmo demonstrates that the universe is expanding and helps to confirm the Big Bang theory.
Chemistry
1 answer:
MatroZZZ [7]2 years ago
7 0

One of the pieces of evidence of the big bang theory where that celestial objects are scattered in the universe because of an explosion that supports the idea of the big bang.

<h3>What is the big bang?</h3>

The big bang is how astronomers explain the way the universe began.

The evidence that I've gathered from the widget that demonstrates that the universe is expanding is that galaxies and other celestial objects are moving away from each other, which is also one of the evidence of the big bang theory where the celestial objects are scattered in the universe because of an explosion that supports the idea of the big bang.

Learn more about the big bang here:

brainly.com/question/18297161

#SPJ1

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Given a gas with an initial volume of 3.0 L and a temperature of 290 K, what is the final volume if the
statuscvo [17]

Answer:

2.8l

Explanation:

just make v2 de subject

6 0
2 years ago
What is the correct scientific notation for 640,000,000? Question 5 options: 6.4X10^8 6.4X10^10 64X10^10 640X10^8
N76 [4]
For very large numbers, it is much more convenient to use scientific notation. To do this, detect first the position of the decimal point. For whole numbers, the decimal point is place implicitly after the very last digit. Then, move this decimal point to the left until you reach to the last digit. In this case, you moved 8 places until you reach 6.4. Because the number is more than 1, the exponent would have a positive sign. Hence, the scientific notation would be 6.4×10⁸.
5 0
4 years ago
How mant grams are there in 7.15 x 10^24 molecules of water?
worty [1.4K]

Answer:

B. 214.02

Explanation:

1 mol of water weighs 18.015 gm and contains 6.023 × 10²³ molecules

From question, We have 7.15 × 10²⁴ molecules

Dividing we get (7.15 × 10 ²⁴) ÷ ( 6.023 × 10²³) = 11.871 molecules

Now, Weight of water = 11.871 × 18.015 = 213.85 which is nearer to option B

4 0
3 years ago
Read 2 more answers
What mass of sucrose (C12H22O11) should be combined with 546 g of water to make a solution with an osmotic pressure of 8.80 atm
lesya [120]

<u>Answer:</u> The mass of sucrose required is 69.08 g

<u>Explanation:</u>

To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

\pi=iMRT

Or,

\pi=i\times \frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}\times RT

where,

\pi = osmotic pressure of the solution = 8.80 atm

i = Van't hoff factor = 1 (for non-electrolytes)

Mass of solute (sucrose) = ?

Molar mass of sucrose = 342.3 g/mol

Volume of solution = 564 mL    (Density of water = 1 g/mL)

R = Gas constant = 0.0821\text{ L.atm }mol^{-1}K^{-1}

T = Temperature of the solution = 290 K

Putting values in above equation, we get:

8.80atm=1\times \frac{\text{Mass of sucrose}\times 1000}{342.3\times 546}\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 290K\\\\\text{Mass of sucrose}=\frac{8.80\times 342.3\times 546}{1\times 1000\times 0.0821\times 290}=69.08g

Hence, the mass of sucrose required is 69.08 g

5 0
3 years ago
What fraction of the gas phase molecules initially present for 1.0 atm in the chamber are present at 1.0×10−10 torr?
vivado [14]

The fraction of gas phase molecules is calculated by the division of final pressure to the initial pressure.

Fraction = \frac{P_{final}}{P_{initial}}     (1)

Here, initial pressure = 1.0 atm

final pressure = 1.0\times 10^{-10} torr

First, convert torr into atm

1 atm = 760 torr

final pressure = \frac{1.0\times 10^{-10}}{760}

= 1.316\times 10^{-13}atm

Now, put the value of initial and final pressure in formula (1)

Fraction = \frac{1.316\times 10^{-13}atm}{1.0 atm}  

= 1.316\times 10^{-13}  

Thus, fraction of the  gas phase molecules = 1.316\times 10^{-13} \simeq 1.3\times 10^{-13}

7 0
4 years ago
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