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GrogVix [38]
1 year ago
10

Match each knee ligament with the correct label

Physics
1 answer:
zalisa [80]1 year ago
8 0

Match each knee ligament with the correct label are:

1. Posterior Talofibular Ligament

2. Calcaneofibular Ligament

3. Anterior Talofibular Ligament

4. Deltoid Ligament

<h3>What is a ligament?</h3>

A ligament is a smaller fibrous tissue that connects bones to other bones, allowing them to be connected strongly but still allowing room to move and bend.

For example, the bones that connect at your elbow are held together by ligaments. They're similar to tendons but on a smaller scale.

Thus, this could be the answer.

To learn more about ligaments click here:

brainly.com/question/12977543

#SPJ1

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What rate do things fall to Earth?
Dima020 [189]

Answer:

9.8 meters per square second

Explanation:

Free Falling Object. the value of g is 9.8 meters per square second on the surface of the earth. The gravitational acceleration g decreases with the square of the distance from the center of the earth. But for many practical problems, we can assume this factor to be a constant.

3 0
3 years ago
What are the developmental stages according to Erikson?
natita [175]

Answer:

1. Trust vs. Mistrust

2. Autonomy vs. Shame

3. Initiative vs. Guilt

4. Industry vs. Inferiority

8 0
3 years ago
With what minimum speed must you toss a 200 g ball straight up to just touch the 14-m-high roof of the gymnasium if you release
Brut [27]
When they say use energy, you want to use

Total energy = potential energy + kinetic energy = mgh + 1/2mv²

I assume you mean 200 g ball,

so, we know the total distance traveled is going to be 13 - 1.3 = 11.7 m

If the ball just makes it to the top ( 13 m ) , then the ball will stop moving and the kinetic energy will be 0,

therefore, the potential energy at the top will be the total energy of the system = mgh

from this, we say that mgh = 1/2mv² solve for v

<span> v = sqrt (2gh) = 15.2 m/s </span>
8 0
3 years ago
The predictions of Rutherford's scattering formula failed to correspond with experimental data when the energy of the incoming a
Vera_Pavlovna [14]

Answer:

The radius of the gold nucleus is 7.1x10⁻¹⁵m

Explanation:

The nearest distance is:

r=\frac{kze^{2} }{mpV^{2} } (eq. 1)

Where

z = atomic number of gold = 79

e = electron charge = 1.6x10⁻¹⁹C

k = electrostatic constant = 9x10⁹Nm²C²

energy of the particle = 32 MeV = 5.12x10⁻¹²J

At the potential energy is zero, all the energy will be kinetic energy:

E_{k} =\frac{1}{2} m V^{2}

Where

m = 4 mp = mass of proton

5.12x10^{-12} =\frac{1}{2} *4*m_{p}* V^{2} \\m_{p}* V^{2} = 2.56x10^{-12}

Replacing in equation 1

r=\frac{9x10^{9}*79*(1.6x10^{-19})^{2}   }{2.56x10^{-12} } =7.1x10^{-15} m

8 0
2 years ago
Calculate the force of a particle with a net charge of 170 coulombs traveling at a speed of 135 meters/second perpendicular to t
amm1812

Answer:

F=1.14N j

Explanation:

The magnitude of the magnetic force over a charge in a constant magnetic field is given by the formula:

|\vec{F}|=|q\vec{v} \ X\ \vec{B}|=qvsin\theta  (|)

In this case v and B vectors are perpendicular between them. Furthermore the direction of the magnetic force is:

-i X k = +j

Finally, by replacing in (1) we obtain:

\vec{F}=(170C)(135\frac{m}{s})(5.0*10^{-5}T)=1.14N\ \hat{j}

hope this helps!

6 0
2 years ago
Read 2 more answers
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