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marshall27 [118]
2 years ago
11

Shyam saw a cylindrical copper rod in his store room he realise that it can be used for various purposes it can be used as a flo

wer ways by covering it one side face with any metal it can be used as a conductor or it can be used as a cylindrical box by covering both the side face with metal he measure the radius of the rod with 3% and length of rod with 7% error error percentage is measuring the volume of the cylinderical box is
Physics
1 answer:
Misha Larkins [42]2 years ago
8 0

The error percentage in measuring the volume of the cylindrical box is 6.3 x 10⁻³ %

<h3>Error percentage in measuring the volume of the cylinder</h3>

The total error percentage in measuring the volume of the cylinder is calculated as follows;

Volume of cylinder = πr²h

Volume of cylinder = π(0.03r)²(0.07h)

Volume of cylinder = (6.3 x 10⁻⁵)πr²h

Error in measuring the volume = 6.3 x 10⁻⁵ x 100% = 6.3 x 10⁻³ %

Learn more about percentage error here: brainly.com/question/5493941

#SPJ1

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Answer:

Convection is the transfer of thermal energy from one place to another by the movement of gas or liquid particles. How does this happen? As a gas or liquid is heated, the substance expands. This is because the particles in liquids and gases gain kinetic energy when they are heated and start to move faster.

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An automobile with a standard differential turns sharply to the left. The left driving wheel turns on a 20-m radius. Distance be
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Explanation:

The given data is as follows.

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where,   V = linear velocity of automobile m/min,

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In the given case, angular velocity remains same for inner and outer wheel but there is change in linear velocity of inner wheel and outer wheel.

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         u = linear velocity of inner wheel

and,   u' = linear velocity of outer wheel.

Formula for angular velocity of inner wheel w = ,

Formula for angular velocity of outer wheel w =

Now, for inner wheels

                   w =

                      = \frac{u}{(R - d)}

                  u = V \times \frac{(R - d)}{R}

                    = V \times (1 - \frac{d}{R})

If radius of wheel is r it will cover  distance in one min.

Since, velocity of wheel is u it will cover distance u in unit time(min)

Thus,             u = 2\pi rn = V \times (1 - \frac{d}{R})

Now, rotation per minute of inner wheel is calculated as follows.

         n = \frac{V}{2 \pi r \times (1 - \frac{d}{R})}

            = \frac{V}{2 \pi r \times (1 - \frac{0.75}{20})} (since 2d = 1.5m given, d = 0.75m),

             = \frac{V}{r} \times 0.1532

So, rotation per minute of outer wheel; n' =  

                   = \frac{V}{2 \pi r \times (1 + \frac{0.75}{20})}

                   = \frac{V}{r} \times 0.1651

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