The combustion reaction of propane would be expressed as:
C3H8 + 5O2 = 3CO2 + 4H2O
To determine the mass of water that is produced from the given amount of propane, we use the mass of propane and the relation of the substances from the balanced reaction. We do as follows:
moles propane = 22 g C3H8 ( 1 mol / 44.1 g ) = 0.50 mol C3H8
moles H2O = 0.50 mol C3H8 ( 4 mol H2O / 1 mol C3H8) = 2 mol H2O
mass H2O = 2 mol H2O ( 18.02 g / 1 mol ) = 36.04 g H2O
Therefore, the mass of water that is produced from 22 grams of propane would be 36.04 g.
Valence électrons don’t define which group You are in so you can cross those choices out.
A would be incorrect because element 1 has 1 valence electron while element 2 has 2 valence electrons.
D would be correct because both elements have two valence electrons.
Also, pls don’t hate if I am wrong!
Answer:freckles with straight hair
Explanation:
Answer:
if charge of ion is positive then it will loose electron
if charge of ion is negative it will gain electron
Solution:
Since we have ml=-1
it shows that it has two 2e- i;e it fond in 2nd subshell in f orbital. And each subshell can hold 2 e-.
Thus the required answer is 2 electrons hold by an atom.
