. How many liters of NH3, at STP, will react with 7.4g O₂?
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18.6
use snells law for glass n=sini/sinr
the value of angle of refraction in glass becomes value of angle of incidence in the glass methanol interface
use snells law again to get the angle light makes with methanol.
The concentration of sodium ions in a solution made by diluting 10.0 mL of a 0.774 M solution of sodium sulfide to a volume of 100 mL would be 0.1548 M.
<h3>Dilution</h3>According to the dilution principle, the number of moles of solutes in a solution before and after dilution must be the same. This is expressed as the following equation:
Where is the molarity before dilution,
is the volume before dilution,
is the molarity after dilution, and
is the volume after dilution.
In this case, = 0.774 M,
= 10.0 mL,
= 100 mL.
=
= 0.774 x 10/100
= 0.0774 M
Thus, the new concentration of the sodium sulfide solution would be 0.0774 M.
Mole of the final solution: 0.0774 x 0.1 = 0.00774 mol
Sodium sulfide formula = --->
Equivalent mole of sodium ion = 0.00774 x 2
= 0.01548 mol
The concentration of sodium ions = mol/volume
= 0.01548/0.1
= 0.1548 M
In other words, the concentration of the sodium ions in the diluted solution would be 0.1548 M.
More on dilution can be found here: brainly.com/question/21323871
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