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2 years ago

. How many liters of NH3, at STP, will react with 7.4g O₂?

Chemistry

1 answer:

iren [92.7K]2 years ago

3 0

Answer:

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Explanation:

kugoidv jugmlirsxnl no me han dicho que no es la que no se me han dicho

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When solving a problem it is important to identify your given and needed units, but it is also important to understand the relat

Angelina_Jolie [31]

Answer:

The question has some details missing. here are the details ; Given the following ;

1. 43.2 g of tablet with 20 cm3 of space

2. 5 cm3 of tablets weighs 10.8 g

3. 5 g of balsa wood with density 0.16 g/cm3

4. 150 g of iron. With density 79g/cm 3

5. 32 cm3 sample of gold with density 19.3 g/cm3

6. 18 ml of cooking oil with density 0.92 g/ml

Explanation:

Appropriate for calculating mass

32 cm3 sample of gold with density 19.3 g/cm3

18 ml of cooking oil with density 0.92 g/ml

Appropriate for calculating volume

5 g of balsa wood with density 0.16 g/cm3

150 g of iron. With density 79g/cm 3

Appropriate for calculating density

43.2 g of tablet with 20 cm3 of space

5 cm3 of tablets weighs 10.8 g

3 0

3 years ago

Describe, on a molecular level, how you would expect these lipids to behave in water.

Gelneren [198K]

Lipids are hydrophobic; They would be insoluble, group together, and float to the top

7 0

3 years ago

What would be the products for the reaction Br2 + KI →? (Just identify the correct products for the reaction. You do not need to

Savatey [412]

Answer: The products of the reaction will be $I_2\text{ and }KBr$

Explanation:

Single displacement reaction is defined as the reaction in which more reactive element displaces a less reactive element from its chemical reaction.

The general chemical equation for the single displacement reaction follows:

$A+BC\rightarrow AC+B$

The given chemical equation follows:

$Br_2+2KI\rightarrow I_2+2KBr$

Bromine element is more reactive than iodine element. Thus, can easily replace iodine from its chemical reaction.

Hence, the products of the reaction will be $I_2\text{ and }KBr$

5 0

3 years ago

Calculate the number of moles of aluminum, sulfur, and oxygen atoms in 4.00 moles of aluminum sulfate, al2(so4)3. express the nu

bagirrra123 [75]

To calculate the number of moles of aluminum, sulfur, and oxygen atoms in 4.00 moles of aluminum sulfate, al2(so4)3. We will simply inspect the "number" of aluminum, sulfur, and oxygen atoms available per one mole of the compound. Here we have Al2(SO4)3, which means that for every mole of aluminum sulfate, there are 2 moles of aluminum, 3 (1 times 3) moles of sulfur, and 12 (4x3) moles of oxygen. Since we have four moles of Al2(SO4)3 given, we simply multiply 4 times the moles present per 1 mole of the compound. So we have 4x2 = 8 moles of Al, 4x3 = 12 moles of sulfur, and 4x12 = 48 moles of oxygen.

So the answer is:
8,12,48

3 0

3 years ago

Read 2 more answers

In a chemical formula such as C6H12O6 and H2O, what do you call the little numbers below the normal line of text.

Morgarella [4.7K]

These are called subscript number.

That is the number below the normal line of test are called subscript number.

This number indicate the indicate the number of atoms of the element present in the chemical formula.

In both of these C₆H₁₂O₆ and H₂O, the number written below the line of the text are called subscript numbers.

3 0

3 years ago

Read 2 more answers