Answer:
No
Explanation:
Some objects gain momentum.
We are given that,
![\frac{dx}{dt} = 4ft/s](https://tex.z-dn.net/?f=%5Cfrac%7Bdx%7D%7Bdt%7D%20%3D%204ft%2Fs)
We need to find
when ![x=8ft](https://tex.z-dn.net/?f=x%3D8ft)
The equation that relates x and
can be written as,
![\frac{x}{6} tan\theta](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7B6%7D%20tan%5Ctheta)
![x = 6tan\theta](https://tex.z-dn.net/?f=x%20%3D%206tan%5Ctheta)
Differentiating each side with respect to t, we get,
![\frac{dx}{dt} = \frac{dx}{d\theta} \cdot \frac{d\theta}{dt}](https://tex.z-dn.net/?f=%5Cfrac%7Bdx%7D%7Bdt%7D%20%3D%20%5Cfrac%7Bdx%7D%7Bd%5Ctheta%7D%20%5Ccdot%20%5Cfrac%7Bd%5Ctheta%7D%7Bdt%7D)
![\frac{dx}{dt} = (6sec^2\theta)\cdot \frac{d\theta}{dt}](https://tex.z-dn.net/?f=%5Cfrac%7Bdx%7D%7Bdt%7D%20%3D%20%286sec%5E2%5Ctheta%29%5Ccdot%20%5Cfrac%7Bd%5Ctheta%7D%7Bdt%7D)
![\frac{d\theta}{dt} = \frac{1}{6sec^2\theta} \cdot \frac{dx}{dt}](https://tex.z-dn.net/?f=%5Cfrac%7Bd%5Ctheta%7D%7Bdt%7D%20%3D%20%5Cfrac%7B1%7D%7B6sec%5E2%5Ctheta%7D%20%5Ccdot%20%5Cfrac%7Bdx%7D%7Bdt%7D)
Replacing the value of the velocity
![\frac{d\theta}{dt} = \frac{1}{6} cos^2\theta (4)^2](https://tex.z-dn.net/?f=%5Cfrac%7Bd%5Ctheta%7D%7Bdt%7D%20%3D%20%5Cfrac%7B1%7D%7B6%7D%20cos%5E2%5Ctheta%20%284%29%5E2)
![\frac{d\theta}{dt} = \frac{8}{3} cos^2\theta](https://tex.z-dn.net/?f=%5Cfrac%7Bd%5Ctheta%7D%7Bdt%7D%20%3D%20%5Cfrac%7B8%7D%7B3%7D%20cos%5E2%5Ctheta)
The value of
could be found if we know the length of the beam. With this value the equation can be approximated to the relationship between the sides of the triangle that is being formed in order to obtain the numerical value. If this relation is known for the value of x = 6ft, the mathematical relation is obtained. I will add a numerical example (although the answer would end in the previous point) If the length of the beam was 10, then we would have to
![cos\theta = \frac{6}{10}](https://tex.z-dn.net/?f=cos%5Ctheta%20%3D%20%5Cfrac%7B6%7D%7B10%7D)
![\frac{d\theta}{dt} = \frac{8}{3} (\frac{6}{10})^2](https://tex.z-dn.net/?f=%5Cfrac%7Bd%5Ctheta%7D%7Bdt%7D%20%3D%20%5Cfrac%7B8%7D%7B3%7D%20%28%5Cfrac%7B6%7D%7B10%7D%29%5E2)
![\frac{d\theta}{dt} = \frac{24}{25}](https://tex.z-dn.net/?f=%5Cfrac%7Bd%5Ctheta%7D%7Bdt%7D%20%3D%20%5Cfrac%7B24%7D%7B25%7D)
Search light is rotating at a rate of 0.96rad/s
I only know #2 and #4.
2.) cells
3.) cells, life , existing
Sorry that i dont know the rest but i took a test on this not to long ago, and i tend to forget stuff once i take a test on it.
The time for half the atoms in a radioactive substance to disintegrate
https://www.vocabulary.com/dictionary/half-life