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irga5000 [103]
2 years ago
7

all white dwarfs have masses in a small range—from about 0.5 to almost 1.4 malchemist sun symbol. why? (select all that apply.)

Physics
1 answer:
Minchanka [31]2 years ago
7 0

A white dwarf cannot support its own weight by its degenerate pressure if its mass is greater than 1.4 solar masses.

<h3>What are white dwarfs?</h3>

White dwarfs are stellar core remnant composed mostly of electron-degenerate matter.

White dwarf is very dense due to its large mass and smaller volume.

<h3>Reasons for comparable mass of white dwarfs and Sun</h3>
  • Stars with main sequence masses less than about 0.5 solar masses cannot ignite the helium fusion required to become white dwarfs.
  • A white dwarf cannot support its own weight by its degenerate pressure if its mass is greater than 1.4 solar masses.

Learn more about white dwarfs here: brainly.com/question/24873876

#SPJ11

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The change in the internal energy of a system that releases 2,500 j of heat and that does 7,655 j of work on the surroundings is
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We are given that the system “releases” heat of 2,500 J, and that it “does work on the surroundings” by 7,655 J.

The highlighted words releases and does work on the surroundings all refers to that it is the system itself which expends energy to do those things. Therefore the action of releasing heat and doing work has both magnitudes of negative value. Therefore:

heat released = - 2, 500 J

work done = - 7, 655 J

Which means that the total internal energy change of the system is:

change in internal energy = heat released + work

<span>change in internal energy = - 2, 500 J +  - 7, 655 J</span>

<span>change in internal energy = -10,155 J</span>

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From the relation above we can conclude that the  as the distance between the two plate increases the electric field strength decreases

Explanation:

I cannot  find any attached photo, but we can proceed anyways theoretically.

The electric field strength (E) at any point in an electric field is the force experienced by a unit positive charge (Q) at that point

i.e

E=\frac{F}{Q}

But the force F

F= \frac{kQ1Q2}{r^2}

But the electric field intensity due to a point charge Q at a distance r meters away is given by

E= \frac{\frac{kQ1Q2}{r^2}}{Q} \\\\\E= \frac{Q1}{4\pi er^2 }

<em>From the relation above we can conclude that the  as the distance between the two plate increases the electric field strength decreases</em>

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Explanation:

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A hydraulic press must be used to press-fit two components together in an assembly process. the system must generate at least 77
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The pressure generated by the piston at the input cylinder must be:

p = F / A = 250 lb-f / 30 in^2


The pressure generated by the piston at the output cylinders is p = F / A = 775 lb-f / A.


Pascal principle rules that both pressures are equal, so:


250 lb-f / 30 in^2 = 775 lb-f / A => A = 775 lb-f * 30 in^2 / 250 lb-f = 93 in^2


Gvien that each output cylinder are 30in^2 you need 93 / 30 = 3.1 cylinders.


Which means that at least you need 4 cylinders to generate a force at least of 775 lb-f.


Answer: 4
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