Question

. A pilot diverted a fighter jet 20.0 km [S 38.0° E] to avoid thunderstorm, and then flew 60.0 km [S 55.0° W] to get back on track. If the diversion lasted a total of 2.00 minutes, what was the average velocity of the jet during the diversion?

Answer 1

The average velocity of the jet during the diversion is 518.75 m/s.

Displacement of the pilot

The displacement of the pilot from the starting position is calculated as follows;

d² = 20² + 60² - 2(20)(60) x cos(θ)

where;

• θ is the angle between 20 km and 60 km leg of triangle formed from the motion.

θ = (90 - 38) + (90 - 55) = 87⁰

d² = 20² + 60² - 2(20)(60) x cos(87)

d² = 3874.39

d = 62.25 km

Average velocity of the pilot

V = total displacement/total time

where;

• time = 2mins = 0.033 hour

V = (62.25 km)/(0.033 hr)

V = 1,867.5 km/hr = 518.75 m/s

Thus, the average velocity of the jet during the diversion is 518.75 m/s.

Learn more about average velocity here: brainly.com/question/6504879

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