What mass of carbon dioxide is produced upon the complete combustion of 17.0 LL of propane (the approximate contents of one 5-ga
1 answer:
The mass of carbon dioxide that is produced will be 31,671 grams or 31.671 kg
<h3>Stoichiometric calculations</h3>First, the equation of the reaction:
The mole ratio of propane burned to carbon dioxide produced is 1:3.
The density of propane gas is 0.621 g/mL, thus, 17.0 L of propane will weigh:
Density = mass/volume, mass = 0.621 g/mL x 17000 = 10,557 g
Mole of 10,557 g of propane = 10557/44.1 = 239.39 moles
Equivalent mole of carbon dioxide produced = 239.39 x 3 = 718.16 moles
Mass of 718.16 moles carbon dioxide = 718.16 x 44.1 = 31,671 grams or 31.671 kg
More on stoichiometric calculations can be found here: brainly.com/question/13384700
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The number of sigma and pi bonds are,
Sigma Bonds = 16
Pi Bonds = 3
Explanation:
Every first bond formed between two atoms is sigma. Pi bond is formed when already a sigma bond is there. While in case of Alkyne (triple Bond) there is one sigma and one pi bond already present, so the third bond is formed by second side-to-side overlap of orbitals, hence, a second pi bond is formed.
Below all black bonds are sigma bonds, while in alkene there is one pi bond and in alkyne there are two pi bonds.
Sigma Bonds = 16
Pi Bonds = 3
Explanation:
Every first bond formed between two atoms is sigma. Pi bond is formed when already a sigma bond is there. While in case of Alkyne (triple Bond) there is one sigma and one pi bond already present, so the third bond is formed by second side-to-side overlap of orbitals, hence, a second pi bond is formed.
Below all black bonds are sigma bonds, while in alkene there is one pi bond and in alkyne there are two pi bonds.
Answer:
B. 1-Butene rightarrow (1) BH3: THF (2)H202, OH-
Explanation:
In the hydroboration of alkenes, an alkene is hydrated to form an alcohol with anti-Markovnikov orientation.
the reagent BH₃:THF is the way that borane is used in organic reactions. The BH₃ adds to the double bond of an alkene to form an alkyl borane. Peroxide hydrogen in basic medium oxidizes the alkyl borane to form an alcohol. Indeed, hydroboration-oxidation converts alkenes to alcohols by adding water through the double bond, with anti-Markovnikov orientation.
