What mass of carbon dioxide is produced upon the complete combustion of 17.0 LL of propane (the approximate contents of one 5-ga
1 answer:
The mass of carbon dioxide that is produced will be 31,671 grams or 31.671 kg
<h3>Stoichiometric calculations</h3>First, the equation of the reaction:
The mole ratio of propane burned to carbon dioxide produced is 1:3.
The density of propane gas is 0.621 g/mL, thus, 17.0 L of propane will weigh:
Density = mass/volume, mass = 0.621 g/mL x 17000 = 10,557 g
Mole of 10,557 g of propane = 10557/44.1 = 239.39 moles
Equivalent mole of carbon dioxide produced = 239.39 x 3 = 718.16 moles
Mass of 718.16 moles carbon dioxide = 718.16 x 44.1 = 31,671 grams or 31.671 kg
More on stoichiometric calculations can be found here: brainly.com/question/13384700
#SPJ1
You might be interested in
Answer:
The addition of sulfate ions shifts equilibrium to the left.
Explanation:
Hello!
In this case, according to the following ionization of strontium sulfate:
It is evidenced that when sodium sulfate is added, sulfate, is actually added in to the solution, which causes the equilibrium to shift leftwards according to the Le Ch athelier's principle. Thus, the answer in this case would be:
The addition of sulfate ions shifts equilibrium to the left.
Best regards!
Answer: 3.024 g grams of hydrogen are needed to convert 76 grams of chromium(III) oxide,
Explanation:
The reaction equation for given reaction is as follows.
Here, 1 mole of reacts with 3 moles of
.
As mass of chromium (III) oxide is given as 76 g and molar mass of chromium (III) oxide is 152 g/mol.
Number of moles is the mass of substance divided by its molar mass. So, moles of is calculated as follows.
Now, moles of .given by 0.5 mol of
is calculated as follows.
As molar mass of is 2.016 g/mol. Therefore, mass of
is calculated as follows.
Thus, we can conclude that 3.024 g grams of hydrogen are needed to convert 76 grams of chromium(III) oxide, .