What mass of carbon dioxide is produced upon the complete combustion of 17.0 LL of propane (the approximate contents of one 5-ga
1 answer:
The mass of carbon dioxide that is produced will be 31,671 grams or 31.671 kg
<h3>Stoichiometric calculations</h3>First, the equation of the reaction:
The mole ratio of propane burned to carbon dioxide produced is 1:3.
The density of propane gas is 0.621 g/mL, thus, 17.0 L of propane will weigh:
Density = mass/volume, mass = 0.621 g/mL x 17000 = 10,557 g
Mole of 10,557 g of propane = 10557/44.1 = 239.39 moles
Equivalent mole of carbon dioxide produced = 239.39 x 3 = 718.16 moles
Mass of 718.16 moles carbon dioxide = 718.16 x 44.1 = 31,671 grams or 31.671 kg
More on stoichiometric calculations can be found here: brainly.com/question/13384700
#SPJ1
You might be interested in
Answer:
Explanation:
4NH₃ (g) + 3O₂ (g) ⇒ 2N₂ (g) + 6H₂ O(1)
Δ
ΔH r =(2ΔH f(N 2 )+6ΔH f (H 2 O(l)))−(4ΔH f (NH 3 (g))+3ΔH f (O 2 (g)))
ΔH rex =[2×0+6×(−286)]−[4×(−46)+3×0]=−1716+186
ΔH rex =−1532kJ/mol
Thermodynamics is a branch of physical chemistry that studies heat and its effects and interactions. Governed by the four main laws, thermodynamics plays a huge role in physics and chemistry, and is also responsible for the law of conservation of energy, a fundamental rule in science.