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Anni [7]
2 years ago
5

Which shows two structures that are made mostly of metal?

Chemistry
2 answers:
Feliz [49]2 years ago
5 0
The bell and the eiffel tower
lesya [120]2 years ago
4 0

Answer:

The bell and the Eiffel tower

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If oxygen is removed from a sample of air as iron nusts, what happens to the partial pressure of oxygen in the air?
trasher [3.6K]

Answer:

It increases because the less oxygen the more pressure there will be on that specific object

Explanation:

3 0
3 years ago
In an experiment, the molar mass of the compound was determined to
sasho [114]
Determine the mass in grams of each element in the sample. If you are given percent composition, you can directly convert the percentage of each element to grams.
For example, a molecule has a molecular weight of 180.18 g/mol. It is found to contain 40.00% carbon, 6.72% hydrogen and 53.28% oxygen.
Convert the percentages to grams.
40.00 grams of carbon
6.72 grams of hydrogen
53.28 grams of oxygen
3 0
3 years ago
Combustion vapor-air mixtures are flammable over a limited range of concentrations. The minimum volume % of vapor that gives a c
DochEvi [55]
Combustion equation of n-hexane:

2C₆H₁₄ + 19O₂ → 12CO₂ + 14H₂O

a)
Assuming we have 100 moles of air,
Oxygen = 20.9 moles
n-hexane required = 20.9/19 x 2
= 2.2 moles

LFL = Half of stoichometric amount = 2.2 / 2 = 1.1
LFL n-hexane = 1.1% 

b)
1.1 volume percent required for LFL

1.1% x 1
= 0.0011 m³ of n-hexane required
6 0
3 years ago
Read 2 more answers
Which equation represents an oxidation-reduction reaction?
bazaltina [42]
In an oxidation-reduction reaction there is an exchange of electrons.


The exchange of electrons implies change in the oxidation states: at least one element increases its oxidation number while other reduces it.


By simple ispection you can predict that in the equation b. there is a change in oxidation states of Cl and Mn.


Now you can check it:


Equation             4H   Cl     +    Mn  O2     ->    Mn  Cl2   + 2H2 O     + Cl2    

oxidation sates   1+  1-             4+   2-              2+   1-         1+   2-         0


The oxidation state of Cl in HCl is 1-  and it changed to 0 in Cl2


The oxidation state of Mn in MnO2 is 4+ and it changed to 2+ in MnCl2 


Answer b.   
3 0
3 years ago
Calculate the energy for the transition of an electron from the n = 5 level to the n = 6 level of a hydrogen atom. E = Joules Is
kramer

Answer:

For an electron to move from a lower energy level to a higher energy , that electron needs to absorb energy sufficient enough to excite it to make the transition. Hence it is an absorption process. The required energy of transition  E = 2.665 x 10⁻²⁰J

Explanation:

Using the Rydberg's equation we can calculate the wavelength of the photon of energy transition as follows:

1/λ = R . (1/nf² - 1/ni²)

where

λ is the required wavelength of the photon needed to be absorbed to excite the electron to transit from level 5 to 6.  

(Note that for the electron to transit to from energy level 5 to 6, the photon would have to fall from level 6 to 5 in order to emit the required energy to excite the electron)

R is the Rydberg's constant 1.097 x 10⁷ m⁻¹

nf is the final level of the photon

ni is the initial level of the photon

1/λ = 1.097 x 10⁷ m⁻¹ (1/5² - 1/6²)

1/λ = 1.3407 x 10⁵ m⁻¹

λ = 7.458 x 10⁻⁶ m

This implies that that is the wavelength of the photon required to excite the electron to transit from energy level 5 to 6. Using the equation below, we can calculate the energy of transition as

E = h.c/λ

where

E is the required energy of transition

h is the Planck's constant (6.626 x 10⁻³⁴ Js)

c is the speed of light (3 x 10⁸ms⁻¹)

λ is the wavelength calculated above

E = 6.626 x 10⁻³⁴ Js  x  3 x 10⁸ms⁻¹/ 7.458 x 10⁻⁶ m

E = 2.665 x 10⁻²⁰J

3 0
3 years ago
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