All categories

1 year ago

Which shows two structures that are made mostly of metal?

Chemistry

2 answers:

Feliz [49]1 year ago

5 0

The bell and the eiffel tower

lesya [120]1 year ago

4 0

Answer:

The bell and the Eiffel tower

You might be interested in

PLEASE HELP!!

lana66690 [7]

Answer:

Explanation:

3 0

2 years ago

Read 2 more answers

Please help me! Will mark brainliest! Thank you!

Kamila [148]

Answer:

gas

Explanation:

8 0

2 years ago

A sample of concrete contains cement, gravel, crushed rocks, sand, and water. Each of these contains different metals and minera

Zepler [3.9K]

As the concrete has cement, gravel, crushed rocks, sand, and water of different physical state and can be separated by physical methods hence it should be called as a mixture.

As the components have significant physical boundaries which clearly identify their presence, the mixture is heterogeneous and not homogeneous.

Thus this is a concrete is a heterogeneous mixture of cement, gravel, crushed rocks, sand, and water

8 0

3 years ago

Catalyst

Hoochie [10]

a. volume of NO : 41.785 L

b. mass of H2O : 18 g

c. volume of O2 : 9.52 L

<h3>Further explanation</h3>

Given

Reaction

4 NH₃ (g) + 5 O2 (g) → 4 NO (g) + 6 H2O (l)

Required

a. volume of NO

b. mass of H2O

c. volume of O2

Solution

Assume reactants at STP(0 C, 1 atm)

Products at 1000 C (1273 K)and 1 atm

a. mol ratio NO : O2 from equation : 4 : 5, so mo NO :

$\tt \dfrac{4}{5}\times 0.5=0.4$

volume NO at 1273 K and 1 atm

$\tt V=\dfrac{nRT}{P}=\dfrac{0.4\times 0.08206\times 1273}{1}=41.785~L$

b. 15 L NH3 at STP ( 1mol = 22.4 L)

$\tt \dfrac{15}{22.4}=0.67~mol$

mol ratio NH3 : H2O from equation : 4 : 6, so mol H2O :

$\tt \dfrac{6}{4}\times 0.67=1$

mass H2O(MW = 18 g/mol) :

$\tt mass=mol\times MW=1\times 18=18~g$

c. mol NO at 1273 K and 1 atm :

$\tt n=\dfrac{PV}{RT}=\dfrac{1\times 35.5}{0.08206\times 1273}=0.34$

mol ratio of NO : O2 = 4 : 5, so mol O2 :

$\tt \dfrac{5}{4}\times 0.34=0.425$

Volume O2 at STP :

$\tt 0.425\times 22.4=9.52~L$

5 0

2 years ago

How many milliliters of a 3.0 M HCL solution are required to make 250.0 milliliters of 1.2 M HCL

tiny-mole [99]

You can use M x V = M' x V'

3 x V = 250 x 1.2

V = 100 ml

5 0

3 years ago