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ruslelena [56]
2 years ago
6

A car accelerates at a rate of 8.8 m/s² with a force from the tires of 15,840 N.

Physics
1 answer:
dezoksy [38]2 years ago
4 0

Answer:

1,800kg

Explanation:

Force = Mass x Acceleration

F = m x a

15840N = m x 8.8

8.8 x m = 15840

m = 15840/8.8

= 1,800kg

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Which competition is the “ most important soccer competition in the world “ ?
Ganezh [65]
It would be B. The World Cup

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Have a great day/night
8 0
3 years ago
A block of mass 200g is oscillating on the end of a horizontal spring of spring constant 100 N/m and natural length 12 cm. When
malfutka [58]

In order to determine the acceleration of the block, use the following formula:

F=ma

Moreover, remind that for an object attached to a spring the magnitude of the force acting over a mass is given by:

F=kx

Then, you have:

ma=kx

by solving for a, you obtain:

a=\frac{kx}{m}

In this case, you have:

k: spring constant = 100N/m

m: mass of the block = 200g = 0.2kg

x: distance related to the equilibrium position = 14cm - 12cm = 2cm = 0.02m

Replace the previous values of the parameters into the expression for a:

a=\frac{(\frac{100N}{m})(0.02m)}{0.2\operatorname{kg}}=10\frac{m}{s^2}

Hence, the acceleration of the block is 10 m/s^2

8 0
1 year ago
The rear window in a car is approximately a rectangle, 1.3 m wide and 0.30 m high. The inside rear-view mirror is 0.50 m from th
maria [59]

Answer:

Height of mirror 0.075 m

width of mirror 0.325 m  

Explanation:

given data

wide = 1.3 m

high = 0.30 m

driver’s eyes = 0.50 m

rear window = 1.50 m

solution

we take here height / width of the mirror  is

height / width   = \frac{h}{w}   .................1

and

height /width of the window is

height /width  = \frac{h_w}{w_w}   .................2

and

distance of eye / window by the mirror is

distance of eye / window = \frac{x_e}{x_w}      .................3

so here

θ = θi  = θr    ....................4

and  tanθ for vertical is

tanθ  = \frac{h}{x_e}  

tanθ  =  \frac{h_w}{(x_e + x_w)}       ....................5

so

h =   h_w \times  \frac{x_e}{(x_e + x_e)}     ....................6

put  here value and we get

h = 0.30 \times  \frac{0.50}{(0.50 + 1.50)}  

h = 0.075 m

and

when we take here tanθ for horizontal than it will be

tanθ = \frac{w}{x_e}    

tanθ = \frac{w_w}{(x_e + x_w)}       .......................7

so

w = w_w \times  \frac{x_e}{(x_e + x_w)}         ....................8

put here value and we get

w = 1.3 \times  \frac{0.50}{(0.50 + 1.50)}  

w = 0.325 m

7 0
3 years ago
If you use a force of 90 N to pick up a 10 pound bag of charcoal, what is the acceleration?
hjlf

Answer:

9ms^2

Explanation:

since ,Force=mass*acceleration

then, acceleration=force/mass

and, Force=90N

Mass=10pound

therefore, acceleration=90/10

=9ms^2

8 0
3 years ago
if you have a block of steel with a density of 7.8g/cm3 and a block of gold with a density of 19.3g/cm3 each with the same volum
natita [175]
Gold because 19.3 is greater than 7.8
3 0
3 years ago
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