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Ne4ueva [31]
2 years ago
11

A Mercedes-Benz 300SL (m = 1700 kg) is parked on a road that rises 15 degrees above the horizontal. What are the magnitudes of (

a) the normal force and (b) the static frictional force that the ground exerts on the tires?
Physics
1 answer:
kogti [31]2 years ago
4 0

Answer: See below

Explanation:

<u>Given:</u>

Mass of the Mercedes-Benz (m) = 1700 kg

Inclination of the road (θ) = 15.0

<em>The free body diagram is shown in figure attached below</em>

<em />

a) The normal force is equal to the cos component of the weight of the car.

\begin{aligned}&f=m g \cos \theta \\&f=1700 \times 9.81 \times \cos 15 \\&f=16108.74 \mathrm{~N}\end{aligned}

b) The static force will be equal to the weight's sin component.

\begin{aligned}&f=m g \sin \theta \\&f=1700 \times 9.81 \times \sin 15 \\&f=4316.32 \mathrm{~N}\end{aligned}

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Answer: 71.7 KJ

Explanation:

The rotational kinetic energy of a rotating body can be written as follows:

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