▸ Exam Instructions

The partial pressures of the gases in a mixture are 0.255 atm 0, 3.24 atm Ny,

katovenus [111]

<h3>Answer:</h3>

4.945 atm

<h3>Explanation:</h3>

Based on Dalton's law of Partial pressure, the total pressure of a mixture of gases is equivalent to the sum of individual partial pressures of the gases in the mixture.

That is;

$Pt = P1+P2+P3+P4+............+ Pn$

In this case;

Partial pressure of Oxygen, P(O) = 0.255 atm

Partial pressure of N, P(N) = 3.24 atm

Partial pressure of Ar, P(Ar) = 1.45 atm

Therefore;

P(total) = P(O) + P(N) + P(Ar)

= 0.255 atm + 3.24 atm + 1.45 atm

= 4.945 atm

Therefore, the total pressure of the mixture is 4.945 atm

6 0

4 years ago

What is the concentration of hydrogen ions in a solution with a pH of 2.36?

Viefleur [7K]

Answer:

b)

Explanation:

$pH = - log[H {}^{ + } ] \\ 2.36 = - log[H {}^{ + } ] \\ [H {}^{ + } ] = {10}^{ - 2.36} \\ [H {}^{ + } ] = 4.37 \times {10}^{ - 3} \: M$

8 0

3 years ago

When zn(oh)2(s) was added to 1.00 l of a basic solution, 1.09×10−2 mol of the solid dissolved. what is the concentration of oh−

uysha [10]

The concentration of the basic solution is determined by:

N = (number of moles / volume of solution)

number of moles = 1.09 x 10^-2 mol
volume of solution = 1 liter
N of basic solution = 1.09 x 10^-2 mol / 1 liter
N = 1.09 x 10^-2 mol/L

The initial concentration of Zn (OH)2 is 0; the basic solution is 1.09x10^-2 M, then the concentration of OH in the final solution is 1.09x10^-2 M

7 0

3 years ago

Read 2 more answers

At 298 K, what is the Gibbs free energy change (ΔG) for the following reaction?

9966 [12]

Answer:

(a). The Gibbs free energy change is 2.895 kJ and its positive.

(b). The Gibbs free energy change is 34.59 J/mole

(c). The pressure is 14924 atm.

(d). The Gibbs free energy of diamond relative to graphite is 4912 J.

Explanation:

Given that,

Temperature = 298 K

Suppose, density of graphite is 2.25 g/cm³ and density of diamond is 3.51 g/cm³.

$\Delta H\ for\ diamond = 1.897 kJ/mol$

$\Delta H\ for\ graphite = 0 kJ/mol$

$\Delta S\ for\ diamond = 2.38 J/(K mol)$

$\Delta S\ for\ graphite = 5.73 J/(K mol)$

(a) We need to calculate the value of $\Delta G$ for diamond

Using formula of Gibbs free energy change

$\Delta G=\Delta H-T\Delta S$

Put the value into the formula

$\Delta G= (1897-0)-298\times(2.38-5.73)$

$\Delta G=2895.3$

$\Delta G=2.895\ kJ$

The Gibbs free energy change is positive.

(b). When it is compressed isothermally from 1 atm to 1000 atm

We need to calculate the change of Gibbs free energy of diamond

Using formula of gibbs free energy

$\Delta S=V\times\Delta P$

$\Delta S=\dfrac{m}{\rho}\times\Delta P$

Put the value into the formula

$\Delta S=\dfrac{12\times10^{-6}}{3.51}\times999\times10130$

$\Delta S=34.59\ J/mole$

(c). Assuming that graphite and diamond are incompressible

We need to calculate the pressure

Using formula of Gibbs free energy

$\beta= \Delta G_{g}+\Delta G+\Delta G_{d}$

$\beta=V(-\Delta P_{g})+\Delta G+V\Delta P_{d}$

$\beta=\Delta P(V_{d}-V_{g})+\Delta G$

Put the value into the formula

$0=\Delta P(\dfrac{12\times10^{-6}}{3.51}-\dfrac{12\times10^{-6}}{2.25})\times10130+2895.3$

$0=-0.0194\Delta P+2895.3$

$\Delta P=\dfrac{2895.3}{0.0194}$

$\Delta P=14924\ atm$

(d). Here, $C_{p}=0$

So, The value of $\Delta H$ and $\Delta S$ at 900 k will be equal at 298 K

We need to calculate the Gibbs free energy of diamond relative to graphite

Using formula of Gibbs free energy

$\Delta G=\Delta H-T\Delta S$

Put the value into the formula

$\Delta G=(1897-0)-900\times(2.38-5.73)$

$\Delta G=4912\ J$

Hence, (a). The Gibbs free energy change is 2.895 kJ and its positive.

(b). The Gibbs free energy change is 34.59 J/mole

(c). The pressure is 14924 atm.

(d). The Gibbs free energy of diamond relative to graphite is 4912 J.

7 0

3 years ago

The final temperature and pressure in a container is 234K at 210 kPa.

andre [41]

Answer:

Initial pressure = 157 kpa (Approx)

Explanation:

Given:

final temperature = 234 K

final pressure = 210 kpa

Initial temperature = 175 K

Find:

Initial pressure

Computation:

Initial pressure / Initial temperature = final pressure / final temperature

Initial pressure / 175 = 210 / 234

Initial pressure = 157 kpa (Approx)

5 0

3 years ago