Question

A soccer ball is kicked from the top of one building with a height of H1 = 30.2 m to another building with a height of H2 = 12.0 m.
The ball is kicked with a speed of v0 = 15.10 m/s at an angle of θ = 74.1° with respect to the horizontal. The mass of a size 5 soccer ball is m = 450 g. When the ball lands on the other building, its speed is 19.89 m/s.
How much energy was lost to air friction? The ball is kicked without a spin.

Answer 1

The amount of energy lost to air friction, given the data is 37.71 J

How to obtain the initial energy

• Initial velocity (u) = 15.1 m/s
• Mass (m) = 450 g = 450 / 1000 = 0.45 Kg
• Initial Energy (E₁) = ?

E₁ = ½mu²

E₁ = ½ × 0.45 × 15.1²

E₁ = 51.3 J

How to obtain the final energy

• Final velocity (u) = 19.89 m/s
• Mass (m) = 450 g = 450 / 1000 = 0.45 Kg
• Final Energy (E₂) = ?

E₂ = ½mv²

E₂ = ½ × 0.45 × 19.89²

E₂ = 89.01 J

How to determine the energy lost

• Initial Energy (E₁) = 51.3 J
• Final Energy (E₂) = 89.01 J
• Energy lost =?

Energy lost = E₂ - E₁

Energy lost = 89.01 - 51.3

Energy lost = 37.71 J

Learn more about energy:

brainly.com/question/10703928

#SPJ1