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2 years ago

What circuit element, an inductor or a capacitor, should be placed in series with the circuit to raise its power factor

Physics

1 answer:

Mumz [18]2 years ago

7 0

Answer:

Inductor should be placed the circuit to raise its power factor.

Explanation:

Inductor:

It is passive component that is used in most electrical circuits to store energy in the form of magnetic energy when electric current flows through it.

It has the function of developing electromotive force in the direction that reduces fluctuation when a fluctuating current flows.

Capacitor:

It is a device for storing electrical energy, consisting of two conductors in close proximity and insulated from each other.

we know that,

Power factor:

cosα = R / Z

cosα = R^2/ (sqrt(R

$cos\alpha =\frac{R}\sqrt{R^{2}(X_{c}-X_{L})^{2} }$

To increase the power factor, denominator should decrease.

from the equation we can say that, the power factor is inversely proportional to X(L)

Hence X(L) should increase.

Therefore, an inductor is required to be connected.

learn more about power factor here:

brainly.com/question/14004507

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A train reaches a speed of 35.0 m/s after accelerating at a rate of 5.00 m/s2 over a distance of 40.0 m. What was the train’s in

MatroZZZ [7]

Answer:

Initial velocity, U = 28.73m/s

Explanation:

Given the following data;

Final velocity, V = 35m/s

Acceleration, a = 5m/s²

Distance, S = 40m

To find the initial velocity (U), we would use the third equation of motion.

V² = U² + 2aS

Where;

V represents the final velocity measured in meter per seconds.

U represents the initial velocity measured in meter per seconds.

a represents acceleration measured in meters per seconds square.

S represents the displacement measured in meters.

Substituting into the equation, we have;

35² = U + 2*5*40

1225 = U² + 400

U² = 1225 - 400

U² = 825

Taking the square root of both sides, we have;

Initial velocity, U = 28.73m/s

5 0

3 years ago

The drag force pushes opposite your motion as you ride a bicycle. If you double your speed, what happens to the drag force?

timurjin [86]

Answer: The drag force goes up by a factor of 4

Explanation:

The Drag Force equation is:

$F_{D}=\frac{1}{2}C_{D}\rho A_{D}V^{2}$ (1)

Where:

$F_{D}$ is the Drag Force

$C_{D}$ is the Drag coefficient, which depends on the material

$\rho$ is the density of the fluid where the bicycle is moving (air in this case)

$A_{D}$ is the transversal area of the body or object

$V$ the bicycle's velocity

Now, if we assume $C_{D}$ , $\rho$ and $A_{D}$ do not change, we can rewrite (1) as:

$F_{D}=C.V^{2}$ (2)

Where $C$ groups all these coefficients.

So, if we have a new velocity $V_{n}$ , which is the double of the former velocity:

$V_{n}=2V$ (3)

Equation (2) is written as:

$F_{D}=C.V_{n}^{2}=C.(2V)^{2}$

$F_{D}=4CV^{2}$ (4)

Comparing (2) and (4) we can conclude the Drag force is four times greater when the speed is doubled.

7 0

3 years ago

The current in a coil with a self-inductance of 1 mH is 2.8 A at t = 0, when the coil is shorted through a resistor. The total r

pogonyaev

Given:

L = 1 mH = $1\times 10^{-3}$ H

total Resistance, R = 11 $\Omega$

current at t = 0 s,

$I_{o}$ = 2.8 A

Formula used:

$I = I_{o}\times e^-{\frac{R}{L}t}$

Solution:

Using the given formula:

current after t = 0.5 ms = $0.5\times 10^{-3} s$

for the inductive circuit:

$I = 2.8\times e^-{\frac{11}{1\times 10^{-3}}\times 0.5\times 10^{-3}}$

$I = 2.8\times e^-5.5$

I =0.011 A

5 0

3 years ago

Cellular telephones use what type of wave?

lana [24]

Cellphones use radio frequency waves to transmit sound through the speaker and the microphone. The radio frequency energy that is given off by cell phones is a type of electromagnetic energy.
I hope I helped! =D

4 0

3 years ago

Read 2 more answers

You have discovered a planet that is one-quarter the radius of Earth (Rp = 1/4R⊕) and one-half as massive (Mp = 1/2M⊕). How does

ExtremeBDS [4]

It's 8 times as much as before.

4 0

3 years ago