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ycow [4]
1 year ago
6

Write a balanced equation for the following redox reaction using the oxidation number method:

Chemistry
1 answer:
Mamont248 [21]1 year ago
3 0

The balanced equation for the following redox reaction using the oxidation number method is as follows:

2K + 2I− + Cl 2 → I2 +2Cl− +2K+

<h3>What is a redox reaction?</h3>

A redox reaction in chemistry is a chemical reaction in which some of the atoms have their oxidation number changed.

According to this question, the following balanced chemical equation is given:

Cl2 (g) + KI (aq) → I2 (s) + KCl (aq)

The oxidation number of the ions in a redox reaction changes, and in this case, the ionic reaction is as follows:

2K + 2I− + Cl 2 → I2 + 2Cl− +2K+

Learn more about redox reaction at: brainly.com/question/13293425

#SPJ1

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A gas has the volume of 45mL at 25 C is heated to 50 C. What is the new volume of the gas? P1V1 = P2V2 V1/T1 = V2/T2 PV = nRT V1
Fudgin [204]

Answer:

Option b (V1/T1 = V2/T2) is the right alternative or the new volume will be "0.048 L".

Explanation:

The given values are:

Temperature,

T₁ = 25°C

or,

   = 298.15 K

T₂ = 50°C

or,

    = 323.15 K

Volume,

V₁ = 45 mL

or,

    = 0.045 L

V₂ = ?

As we know,

⇒  \frac{V_1}{T_1} =\frac{V_2}{T_2}

Or,

⇒  V_2=\frac{V_1\times T_2}{T_1}

On substituting the values, we get

⇒       =\frac{0.045\times 323.15}{298.15}

⇒       =\frac{14.541}{298.15}

⇒       =0.048 \ L

7 0
1 year ago
Which is an example of pure chemistry
Alexeev081 [22]

Examples of pure substances include tin, sulfur, diamond, water, pure sugar, table salt and baking soda. Crystals, in general, are pure substances. Tin, sulfur, and diamond are examples of pure substances which are chemical elements. All elements are pure substances.

5 0
2 years ago
Consider the following system at equilibrium where H° = -87.9 kJ, and Kc = 83.3, at 500 K. PCl3(g) + Cl2(g) PCl5(g) If the VOLUM
7nadin3 [17]

Answer:

The value of Kc C. remains the same.

The value of Qc C. is less than Kc.

The reaction must: A. run in the forward direction to reestablish equilibrium

The number of moles of Cl2 will  B. decrease.

Explanation:

Le Chatelier's Principle states that if a system in equilibrium undergoes a change in conditions, it will move to a new position in order to counteract the effect that disturbed it and recover the state of equilibrium.

A decrease in volume causes the system to evolve in the direction in which there is less volume, that is, where the number of gaseous moles is less.

But temperature is the only variable that, in addition to influencing equilibrium, modifies the value of the constant Kc. So if the volume of the equilibrium system is suddenly decreased at constant temperature: <u><em>The value of Kc remains the same.</em></u>

<u><em> </em></u>As mentioned, if the volume of an equilibrium gas system decreases, the system moves to where there are fewer moles. In this case, being:

PCl₃(g) + Cl₂(g) ⇔ PCl₅(g)

The equilibrium in this case then shifts to the right because there is 1 mole in the term on the right, compared to the two moles on the left. So, <u><em>The reaction must: A. run in the forward direction to reestablish equilibrium</em></u>.

By decreasing the volume, and so that Kc remains constant, being:

Kc=\frac{[PCl_{5} ]}{[PCl_{3}]*[Cl_{2}  ]}=\frac{\frac{nPCl_{5} }{Volume} }{\frac{nPCl_{3}}{Volume}*\frac{nCl_{2} }{Volume}  } =\frac{nPCl_{5}}{nPCl_{3}*nCl_{2}} *Volume

 where nPCl₅, nPCl₃ and nCl₂ are the moles in equilibrium of PCl₅, PCl₃ and Cl₂

so,  the number of moles of Cl₂ should decrease.<u><em>The number of moles of Cl2 will  B. decrease.</em></u>

If the reaction quotient is less than the equilibrium constant, Qc <Kc, the system will evolve to the right, the direct reaction prevailing, to increase the concentration of products. So in this case, if the reaction moves to the right, <em><u>the value of Qc C. is less than Kc.</u></em>

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I'm Guessing A since it takes about 0.01°C temperature and around 600 <span>p</span><span>ascals<span> </span></span>of pressure 
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