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pishuonlain [190]
2 years ago
14

Using the formula for work, Match the Force × Distance problems with their correct "Work Performed" answer. The first example ha

s been completed for you.
Force × Distance = Work Performed

10 newtons 6 meters =60 Nm

1. 62 Nm
40 pounds 100 feet

2. 4000ft.-lbs.
2.5 pounds 24 inches

3. 5 ft.-lbs
62 newtons 1 meter

4. 200ft.-lbs.
1 ton 20 feet

5. 40,000 ft.-lbs.
400 pounds 0.5 feet
Physics
1 answer:
Alenkinab [10]2 years ago
3 0
1. 62NM = 62 newtons 1 meter
2. 4000ft.-lbs = 40 pounds 100 feet
3. 5ft.-lbs = 2.5 pounds 24 inches
4. 200ft.-lbs = 400 pounds 0.5 feet
5. 40,000 ft.-lbs = 1 ton 20 feet
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The radius of the aorta is «10 mm and the blood flowing through it has a speed of about 300 mm/s. A capillary has a radius of ab
stealth61 [152]

Answer:

(I). The effective cross sectional area of the capillaries is 0.188 m².

(II). The approximate number of capillaries is 3.74\times10^{9}

Explanation:

Given that,

Radius of aorta = 10 mm

Speed = 300 mm/s

Radius of capillary r=4\times10^{-3}\ mm

Speed of blood v=5\times10^{-4}\ m/s

(I). We need to calculate the effective cross sectional area of the capillaries

Using continuity equation

A_{1}v_{1}=A_{2}v_{2}

Where. v₁ = speed of blood in capillarity

A₂ = area of cross section of aorta

v₂ =speed of blood in aorta

Put the value into the formula

A_{1}=A_{2}\times\dfrac{v_{2}}{v_{1}}

A_{1}=\pi\times(10\times10^{-3})^2\times\dfrac{300\times10^{-3}}{5\times10^{-4}}

A_{1}=0.188\ m^2

(II). We need to calculate the approximate number of capillaries

Using formula of area of cross section

A_{1}=N\pi r_{c}^2

N=\dfrac{A_{1}}{\pi\times r_{c}^2}

Put the value into the formula

N=\dfrac{0.188}{\pi\times(4\times10^{-6})^2}

N=3.74\times10^{9}

Hence, (I). The effective cross sectional area of the capillaries is 0.188 m².

(II). The approximate number of capillaries is 3.74\times10^{9}

3 0
3 years ago
What causes fusion to stop within all stars?
puteri [66]
Hello!

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Hope this helps!
4 0
3 years ago
What’s the kinetic energy of the object? Use .
kirill115 [55]
We have: K.E. = mv² / 2
here, m = 4 Kg
v = 9 m/s

Substitute their values into the expression:
K.E. = (4)(9)² / 2
K.E. = (4)(81) / 2
K.E. = 324 / 2
K.E. = 162 Joules

In short, Your Answer would be 162 J

Hope this helps!

5 0
3 years ago
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