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nadya68 [22]
2 years ago
14

If the ocular lens magnifies a specimen 10x, and the objective lens used magnifies the specimen 35x. What is the total magnifica

tion being used to observe the specimen?
Physics
1 answer:
Kay [80]2 years ago
8 0

Answer:

350x^2

Explanation:

I'm assuming you're saying you're using them together, like stacking them on top of each other, so if that's the case then this is a simple multiplication problem, which can be written as 10x(35x). Solve it and you get 350x^2.

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A ray of light is incident on a body x what is the reftactive index​
evablogger [386]

Answer:

1.63

Explanation:

If you have the following options:

<u>A.  1.63</u>

B.  1.50

C.  1.49

D.  1.33

E.  1.02

6 0
3 years ago
What does this tell you about the direction and magnitude of the acceleration acting on the cannonball throughout its duration o
Lyrx [107]

Answer:

Direction remains the same but velocity changes.

Explanation:

This tell us about the direction and magnitude of the acceleration acting on the cannonball throughout its duration of flight that its direction remains the same but its magnitude of the acceleration is continuously changing. The cannonball moves in the direction in which the cannon was fired while the velocity is highest after the fire but decreases when goes higher and when it comes back to the ground so its velocity increases against so we can say that both positive and negative acceleration occurs. Positive acceleration means increase in the magnitude of velocity whereas negative acceleration means decrease in velocity.

3 0
3 years ago
A man exerts a constant force to pull a 51-kg box across a floor at constant speed. He exerts this force by attaching a rope to
Vitek1552 [10]

Answer:

W=561.41 J

Explanation:

Given that

m = 51 kg

μk = 0.12

θ = 36.9∘

Lets F is the force applied by man

Given that block is moving at constant speed it mans that acceleration is zero.

Horizontal force = F cos θ

Vertical force = F sinθ

Friction force Fr=  μk N

N +  F sinθ = m g

N = m g -  F sinθ

Fr =  μk (m g -  F sinθ)

For equilibrium

F cos θ =  μk (m g -  F sinθ)

F ( cos θ +μk  sinθ)  = μk (m g

Now by putting the values

F ( cos 36.9∘ + 0.12 x sin36.9∘)=0.12 x 51 x 10

F= 70.2 N

We know that Work

W= F cos θ .d

W= 70.2 x cos 36.9∘ x 10

W=561.41 J

3 0
4 years ago
How can a megaphone used by a cheerleader allow people on the opposite side of a field to hear her better?
Goshia [24]
The megaphone is cupping the area around her mouth and it is like with your hands, if you cover around them the noise will be louder. It is because it is hollow and there isn't anything to block the noise through the megaphone.
7 0
3 years ago
15 POINTS
zhenek [66]

Answer:

Acceleration of the bullet while moving into the clay is -312500 ms⁻²

Explanation:

Given data

Initial velocity (v₁) = 250 m/s                 Final velocity (v₂) = 0 m/s

Distance (s)= 0.1 m                            acceleration (a) = ?

Using 3rd equation of motion

                  2as = v₂²- v₁²

       2 × a × 0.1 = 0² - 250²

            0.2 × a = -62500

                      a = -62500/0.2

                     a = -312500 m/s²

Here negative sign indicate that bullet slow down and it is deceleration i.e negative acceleration.

3 0
3 years ago
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