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Maru [420]
2 years ago
7

7. A movable piston is allowed to cool from 392°F to 104°F. If the initial volume is 105 mL,

Chemistry
1 answer:
-BARSIC- [3]2 years ago
5 0

Answer:

27.9 mL

Explanation:

To find the new volume, you need to use the Charles' Law equation:

V₁ / T₁ = V₂ / T₂

In this equation, "V₁" and "T₁" represent the initial volume and temperature. "V₂" and "T₂" represent the final volume and temperature.

V₁ = 105 mL                     V₂ = ? mL

T₁ = 392 °F                       T₂ = 104 °F

V₁ / T₁ = V₂ / T₂                                            <----- Charles' Law

105 mL / 392 °F = V₂ / 104 °F                     <----- Insert values

0.26785 = V₂ / 104 °F                                 <----- Simplify left side

27.9 = V₂                                                     <----- Multiply both sides by 104

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Combined with Boyle's law and Gay Lussac's law  

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