Considering the definition of pOH and strong base, the pOH of the aqueous solution is 1.14
The pOH (or potential OH) is a measure of the basicity or alkalinity of a solution and indicates the concentration of ion hydroxide (OH-).
pOH is expressed as the logarithm of the concentration of OH⁻ ions, with the sign changed:
pOH= - log [OH⁻]
On the other hand, a strong base is that base that in an aqueous solution completely dissociates between the cation and OH-.
LiOH is a strong base, so the concentration of the hydroxide will be equal to the concentration of OH-. This is:
[LiOH]= [OH-]= 0.073 M
Replacing in the definition of pOH:
pOH= -log (0.073 M)
<u><em>pOH= 1.14 </em></u>
In summary, the pOH of the aqueous solution is 1.14
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Answer:
Elements in same group have same chemical properties due to same number of valence electrons in valence shell.
Explanation:
Chemical properties are those properties which results in transforming the starting material to a entirely new substance with different chemical and physical properties. This transformation takes place after a chemical reaction. Hence, the chemical reactivity of some atoms is greater than the others and vice versa.
In periodic table it is found that the elements in the same group have almost same chemical behaviour. For example, elements of group 8 (or 18) are almost non reactive, while that of group 1 and group 7 are found very reactive and show same chemical behaviour like group 1 elements forms +1 ion while group 7 elements form -1 ions as the group 1 metals have single valence shell electron which upon losing allow the atom to attain stability and the halogen having 7 electrons in valence shell upon accepting one electron allow them to attain a octet of stability respectively.
3. photosynthesis , 5. carbon dioxide , second blank of #2 is fossil fuels
Explanation:
Experiment Initial [CS2] (mol/L) Initial Rate (mol/L·s)
1 0.100 2.7 × 10−7
2 0.080 2.2 × 10−7
3 0.055 1.5 × 10−7
4 0.044 1.2 × 10−7
a) Choose the rate law for the decomposition of CS2.
Comparing equations 1 and 3, reducing the initial concentration by almost half (from 0.100 to 0.055) leads too the rate of reaction to be reduced by almost half (from 2.7 × 10−7 to 1.5 × 10−7).
This signifies that the reaction is a first order reaction.
Rate = k [CS2]
(b) Calculate the average value of the rate constant.
Taking equation 1.
Rate = k [CS2]
k = Rate / [CS2]
k = 0.100 / (2.7 × 10−7) = 0.037 x 10^8 = 3.7 x 10^6s-1
A wavelength's frequency and energy (E) drop as it becomes longer. You may conclude from these equations that the wavelength grows shorter as the frequency rises. The wavelength lengthens as the frequency drops.
Since frequency and wavelength are inversely related to one another, the wavelength of the wave falls as frequency increases.
