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Pie
2 years ago
7

Would you expect a heavily crosslinked polyethylene that has a glass-transition temperature of 0°c to be an elastomer, a thermos

et (nonelastomer), or a thermoplastic polymer at room temperature?
Chemistry
1 answer:
musickatia [10]2 years ago
4 0

The heavily crosslinked polyethylene that has a glass-transition temperature of 0°c to be an <u>thermoset (non-elastomer).</u>

A cross-linked kind of polyethylene has been known as cross-linked polyethylene, sometimes known by the acronyms PEX, XPE, or XLPE. It must be primarily utilized in residential water piping, high tension electrical cable insulation, hydronic radiant heating as well as cooling systems, construction management pipework systems, and infant play mats.

Tanks composed of linear polyethylene as well as XLPE are both constructed using heated resins to produce cured plastic. But because of the variations in how they are produced, the polyethylenes they produce have extremely varied structural strengths. Simply put, cross-linking is just the creation of links between polymer chains.

Therefore, the correct answer will be option (a).

To know more about polyethylene

brainly.com/question/15913091

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Answer: 0.17M

Explanation:

The equation for the reaction is :

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From the balanced equation, we obtain :

nA = mole of acid = 2

nB = mole of the base = 1

From the question, we obtain:

Va = Vol. Of acid = 0.105L

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Mb = conc. of base = 0.25M.

We solve for the conc. of the acid using:

MaVa / Mb Vb = nA / nB

(Ma x 0.105) / (0.25x0.0357) = 2

Cross multiply to express in linear form. We have:

Ma x 0.105 = 0.25 x 0.0357 x 2

Divide both side by 0.105. We have

Ma = (0.25 x 0.0357 x 2) / 0.105

Ma = 0.17M

Therefore the concentration of the acid(HNO3) is 0.17M

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