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antoniya [11.8K]
2 years ago
13

What mass of au is produced when 0.0500 mol of au2s3 is reduced completely with excess h2?

Chemistry
1 answer:
olga_2 [115]2 years ago
7 0

The mass of Au is 19.7 g

The chemical reaction may be

Au₂S₃ + 3H₂ → 2Au + 3H₂S

1 mole of Au₂S₃ gives 2 mole of Au

Then 0.0500 mol of Au₂S₃ gives

0.0500 × 2 / 1

= 0.10 moles.

To find mass

Mass = moles × molar mass

Moles = 0.10.

Molar mass = 197 g

Mass = 0.10 × 197

         = 19.7 g

Hence the mass of Au produces is 19.7 g

Learn more about mass on

brainly.com/question/24550995

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